It depends on the concentration of HCl in the solution.
To find the moles of HCl, first calculate the millimoles of HCl in 50 mL: 4.0 mol/L * 50 mL = 200 mmol. Then convert millimoles to moles by dividing by 1000: 200 mmol / 1000 = 0.2 moles of HCl. Therefore, there are 0.2 moles of HCl in 50 mL of 4.0 M HCl.
There are 0.020 moles of HCl dissolved in 200 ml of 0.100 M HCl solution. This is calculated by multiplying the volume of the solution by the molarity of the solute.
To find the number of moles of solute in the solution, first, calculate the amount of HCl in grams using the formula: moles = molarity x volume (in liters). Then, convert the grams of HCl to moles by dividing by the molar mass of HCl (36.46 g/mol).
To find the number of moles, first calculate the number of moles of HCl in the 50 mL solution by multiplying the volume (in liters) by the molarity. Volume in liters = 50 mL / 1000 mL/L = 0.05 L Moles = 0.05 L * 6.0 mol/L = 0.3 moles of HCl.
1 mole of HCl reacts with 1 mole of KOH. Therefore, 0.5 moles of KOH (500 mL = 0.5 L) are needed to neutralize 0.5 moles of HCl.
0.0747mol/L of HCL 1.81mol/L of water
To find the moles of HCl, first calculate the millimoles of HCl in 50 mL: 4.0 mol/L * 50 mL = 200 mmol. Then convert millimoles to moles by dividing by 1000: 200 mmol / 1000 = 0.2 moles of HCl. Therefore, there are 0.2 moles of HCl in 50 mL of 4.0 M HCl.
There are 0.020 moles of HCl dissolved in 200 ml of 0.100 M HCl solution. This is calculated by multiplying the volume of the solution by the molarity of the solute.
To find the number of moles of solute in the solution, first, calculate the amount of HCl in grams using the formula: moles = molarity x volume (in liters). Then, convert the grams of HCl to moles by dividing by the molar mass of HCl (36.46 g/mol).
To find the number of moles, first calculate the number of moles of HCl in the 50 mL solution by multiplying the volume (in liters) by the molarity. Volume in liters = 50 mL / 1000 mL/L = 0.05 L Moles = 0.05 L * 6.0 mol/L = 0.3 moles of HCl.
1 mole of HCl reacts with 1 mole of KOH. Therefore, 0.5 moles of KOH (500 mL = 0.5 L) are needed to neutralize 0.5 moles of HCl.
There are 15 moles of HCl present in 75 mL of a 200 M solution. To calculate this, first convert 75 mL to liters (0.075 L), then use the formula Molarity = moles/volume to find moles. So, 200 M = x moles / 0.075 L. Solving for x gives you 15 moles of HCl.
The moles of NaOH at the equivalence point are equal to the moles of HCl initially present. So, moles of NaOH = 0.24 mol/L * 0.035 L = 0.0084 moles. Since the moles of HCl are the same, and we have 50 ml = 0.05 L HCl, the concentration of HCl is 0.0084 moles / 0.05 L = 0.168 M.
Just multiply 25 mL and 4.0 M but convert 25 mL to liter making it 0.025 L. 0.025 L * 4 M = 0.1 moles
you cant solve that without the concentration of the HCl or the mass if you have either of these use: To find the moles with mass of HCl you have use n= m/mm , m=mass of HCl and mm = the molar mass so the elements mass combined from periodic table to find the moles with the volume = 0.06 (in litres must be!) and concentration use n = cv
The concentration of a solution is given by the formula: concentration = moles of solute / volume of solution in liters. However, to determine the concentration in this case, we need to know the moles of HCl in the solution. Given that the concentration is 0.5 M, it means there are 0.5 moles of HCl in every liter of solution. To find out how many moles are in 400 ml (0.4 L) of 0.5 M HCl solution, we use the formula: moles = concentration x volume. moles = 0.5 M x 0.4 L = 0.2 moles. Therefore, the concentration of 400 ml of 0.5 M HCl solution is 0.5 M.
The equation you need is:M1*V1=M2*V2V1= 5 ml HCLV2= 4.76mL NaOHM2= 0.9581M1= M2*V2/M1Plug your numbers into the equation and you'll be done.