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you cant solve that without the concentration of the HCl or the mass if you have either of these use:

To find the moles with mass of HCl you have use

n= m/mm , m=mass of HCl and mm = the molar mass so the elements mass combined from Periodic Table

to find the moles with the volume = 0.06 (in litres must be!) and concentration use

n = cv

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12y ago
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13y ago

Molarity = moles of solute/Liters of solution ( 25 ml = 0.025 Liters )

0.10 M HCl = moles HCl/0.025 Liters

= 0.0025 moles HCl

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10y ago

54.7 g

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Q: How many moles of HCL gas are contained in 25 ml of a 0.10 M solution of the acid?
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