This value is 0,06 moles.
The solution is 0,25 M.
The definition of 0.175 m KF is that 1 kg of water contains 0.175 moles of KF. Thus, 347 g of water is equivalent to 0.347 kg, and to find moles of KF, you calculate as follows:0.175 moles/Kg x 0.347 kg = 0.0607 moles of KF are present (3 significant figures).
Moles of solute/ kg of solvent = 2 molal solution
The moles number of water 12; the chemical formula is KAl(SO4)2.12H2O.
3 moles in 1 liter = 3 M
no
The solution is 0,25 M.
0.375
Molarity = moles of solute/Liters of solution Molarity = 10 moles salt/20 Liters solution = 0.50 M salt solution ----------------------------
The definition of 0.175 m KF is that 1 kg of water contains 0.175 moles of KF. Thus, 347 g of water is equivalent to 0.347 kg, and to find moles of KF, you calculate as follows:0.175 moles/Kg x 0.347 kg = 0.0607 moles of KF are present (3 significant figures).
Not if the solution contained only glucose and water.
Moles of solute/ kg of solvent = 2 molal solution
The moles number of water 12; the chemical formula is KAl(SO4)2.12H2O.
In one mole of this solution, there are seven moles of H2O.
1620 ml = 1.62 Liters Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/1.62 Liters = 1 M NaOH solution ===============
3.33 degrees Celsius is the freezing point of a solution that contains 0.550 moles of Nal in 615 g of water.
The freezing point of a solution that contains 0.550 moles of NaI in 615 g of water is -3.33 degrees Celsius.