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How many grams of acetic acid would you use to make 10 liters of a 0.1 Mole aqueous solution of acetic acid?
C2H4O2 Find moles first. Molarity = moles of solute/Liters of solution moles C2H4O2 = molarity/Liters solution moles C2H4O2 = 0.1 M/10 L = 0.01 moles C2H4O2 -----------------------------------now, molar mass time moles 0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2) = 0.60 grams acetic acid needed --------------------------------------------
20 ml of acetic acid is titrated with a solution of 0.15 M NaOH If 35 ml of NaOH are required to reach the equivalence point what is the concentration of the acetic acid solution?
The moles of NaOH at the equivalence point will equal the moles of acetic acid present in the solution. Therefore, using the volume and concentration of NaOH used at the equivalence point, you can calculate the moles of NaOH used. Then, based on the stoichiometry of the reaction, you can determine the moles of acetic acid, and finally, determine the concentration of the acetic acid solution.
How many moles of acetic anhydride were represented by 6.00 ml density1.08 gml?
To find the number of moles of acetic anhydride in 6.00 ml, we need to first calculate its mass using the density formula: mass = volume * density. Mass = 6.00 ml * 1.08 g/ml = 6.48 g Next, we need to convert the mass to moles using the molar mass of acetic anhydride. Acetic anhydride has a molar mass of approximately 102.09 g/mol. Moles = 6.48 g / 102.09 g/mol ≈ 0.063 moles Therefore, there are approximately 0.063 moles of acetic anhydride in 6.00 ml.
How many mL of 0.55 M NaOH would be required to reach the equivalence point for 25.0 mL of a 0.75 M solution of acetic acid?
To determine the volume of 0.55 M NaOH needed to reach the equivalence point with 25.0 mL of 0.75 M acetic acid, you need to use the stoichiometry of the reaction. Acetic acid reacts with NaOH in a 1:1 ratio, so moles of acetic acid equals moles of NaOH at the equivalence point. Calculate moles of acetic acid from its concentration and volume, equate it to moles of NaOH, and then calculate the volume of NaOH solution needed.
How many molecules are there in 60.0g of acetic acid C2H402?
Find the moles using the formula: moles= grams/molecular mass In this case, molecular mass = 24+4+32 = 60g/mol so 66/60 = 1.1 moles Then, using avogadro's constant, work out the number of molecules. n(molecules) = number of moles x 6.02x10^23 =1.1x 6.02x 10^23 =?
How many moles of acetic acid C H3COOH a re contained within 21.71g of acetic acid?
Molar mass of ethanoic acid = (1x12) + (3x1) + (1x12) + (2x16) + (1x1) = 60 no. of moles = mass/ molar mass = 21.71/60 = 0.362 moles
How many moles of formic acid is there in 25 grams of acetic acid?
I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================
How many grams of acetic acid would you use to make 10 liters of a 0.1 Mole aqueous solution of acetic acid?
C2H4O2 Find moles first. Molarity = moles of solute/Liters of solution moles C2H4O2 = molarity/Liters solution moles C2H4O2 = 0.1 M/10 L = 0.01 moles C2H4O2 -----------------------------------now, molar mass time moles 0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2) = 0.60 grams acetic acid needed --------------------------------------------
20 ml of acetic acid is titrated with a solution of 0.15 M NaOH If 35 ml of NaOH are required to reach the equivalence point what is the concentration of the acetic acid solution?
The moles of NaOH at the equivalence point will equal the moles of acetic acid present in the solution. Therefore, using the volume and concentration of NaOH used at the equivalence point, you can calculate the moles of NaOH used. Then, based on the stoichiometry of the reaction, you can determine the moles of acetic acid, and finally, determine the concentration of the acetic acid solution.
How many moles are contained in 22.23 g KBr-?
0.1868 moles
How many moles of acetic anhydride were represented by 6.00 ml density1.08 gml?
To find the number of moles of acetic anhydride in 6.00 ml, we need to first calculate its mass using the density formula: mass = volume * density. Mass = 6.00 ml * 1.08 g/ml = 6.48 g Next, we need to convert the mass to moles using the molar mass of acetic anhydride. Acetic anhydride has a molar mass of approximately 102.09 g/mol. Moles = 6.48 g / 102.09 g/mol ≈ 0.063 moles Therefore, there are approximately 0.063 moles of acetic anhydride in 6.00 ml.
How many moles are contained in 0.455L of a 7.182 M solution?
This is a chemical calculation. there are 3.267 moles in this solution.
How many mL of 0.55 M NaOH would be required to reach the equivalence point for 25.0 mL of a 0.75 M solution of acetic acid?
To determine the volume of 0.55 M NaOH needed to reach the equivalence point with 25.0 mL of 0.75 M acetic acid, you need to use the stoichiometry of the reaction. Acetic acid reacts with NaOH in a 1:1 ratio, so moles of acetic acid equals moles of NaOH at the equivalence point. Calculate moles of acetic acid from its concentration and volume, equate it to moles of NaOH, and then calculate the volume of NaOH solution needed.
How many atoms are contained in 5.26 moles of oxygen?
5,26 moles of oxygen contain 31,676.10e23 atoms.
How many atoms are contained in 2 moles of neon?
Two moles of neon contain 12,044281714.10e23 atoms.
How many moles of atom contained in 0.688 g Ca?
0,688 g calcium is equivalent to 0,017 moles.
How many grams is contained in 0.27 moles of calcium?
0,27 moles of calcium contain 10,82 g calcium.
