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Reaction mechanism of acetic anhydride with water?
1. A lone pair on oxygen of water attacks a carbon in acetic anhydride, forcing one of the bonds in the carbonyl group (of acetic anhydride) to move onto its oxygen (oxygen of carbonyl group). The oxygen now has a negative charge and water is attached to the carbon that was once doubly bonded to oxygen. The water now has a positive charge, making it an oxonium ion. 2. The lone pair of electrons on the negatively charged oxygen (of the former carbonyl group) moves back down, forming a double bond again with carbon. 3. Carbon now has a negative charge so it has to get rid of it by breaking its bond with oxygen (the one in the middle of the anhydride). You now have 2 molecules. 4. The positive charge of water has to also go away so it loses a hydrogen. You now have one molecule of acetic acid. 5. The hydrogen attaches onto the oxygen that was broken away from carbon (but still attached to the carbonyl group of the other untouched carbon). And you now have your second molecule of acetic acid. So for every mole of acetic anhydride and water, you form 2 moles of acetic acid. It may be hard to understand this but i have a link for you if you are still confused.
How many moles of acetic acid are contained within 24.71g of acetic acid?
To find the number of moles, we first need to calculate the molar mass of acetic acid (CH3COOH). The molar mass is 60.05 g/mol. Next, we can use the formula: number of moles = mass / molar mass number of moles = 24.71g / 60.05 g/mol This gives us approximately 0.41 moles of acetic acid.
Difference between 0.1 M acetic acid and glacial acetic acid?
Glacial acetic acid doesn't have water in it. Acetic acid ordinarily would be in a solution. Acetic acid is a weak acid, but it can be very concentrated. Glacial acetic acid is a acetic acid of a high purity more then 99.75 %
How many grams of acetic acid would you use to make 10 liters of a 0.1 Mole aqueous solution of acetic acid?
C2H4O2 Find moles first. Molarity = moles of solute/Liters of solution moles C2H4O2 = molarity/Liters solution moles C2H4O2 = 0.1 M/10 L = 0.01 moles C2H4O2 -----------------------------------now, molar mass time moles 0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2) = 0.60 grams acetic acid needed --------------------------------------------
20 ml of acetic acid is titrated with a solution of 0.15 M NaOH If 35 ml of NaOH are required to reach the equivalence point what is the concentration of the acetic acid solution?
The moles of NaOH at the equivalence point will equal the moles of acetic acid present in the solution. Therefore, using the volume and concentration of NaOH used at the equivalence point, you can calculate the moles of NaOH used. Then, based on the stoichiometry of the reaction, you can determine the moles of acetic acid, and finally, determine the concentration of the acetic acid solution.
Reaction mechanism of acetic anhydride with water?
1. A lone pair on oxygen of water attacks a carbon in acetic anhydride, forcing one of the bonds in the carbonyl group (of acetic anhydride) to move onto its oxygen (oxygen of carbonyl group). The oxygen now has a negative charge and water is attached to the carbon that was once doubly bonded to oxygen. The water now has a positive charge, making it an oxonium ion. 2. The lone pair of electrons on the negatively charged oxygen (of the former carbonyl group) moves back down, forming a double bond again with carbon. 3. Carbon now has a negative charge so it has to get rid of it by breaking its bond with oxygen (the one in the middle of the anhydride). You now have 2 molecules. 4. The positive charge of water has to also go away so it loses a hydrogen. You now have one molecule of acetic acid. 5. The hydrogen attaches onto the oxygen that was broken away from carbon (but still attached to the carbonyl group of the other untouched carbon). And you now have your second molecule of acetic acid. So for every mole of acetic anhydride and water, you form 2 moles of acetic acid. It may be hard to understand this but i have a link for you if you are still confused.
How many moles of formic acid is there in 25 grams of acetic acid?
I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================
How many moles of acetic acid are contained within 24.71g of acetic acid?
To find the number of moles, we first need to calculate the molar mass of acetic acid (CH3COOH). The molar mass is 60.05 g/mol. Next, we can use the formula: number of moles = mass / molar mass number of moles = 24.71g / 60.05 g/mol This gives us approximately 0.41 moles of acetic acid.
How many moles of water are produced when ethylene glycol reacts with phtalic anhydride?
The balanced chemical equation for the reaction between ethylene glycol and phthalic anhydride is: C6H4(CO)2O + 2 C2H6O2 → C6H4(CO2CH2CH2O)2 + 2 H2O From the equation, it can be seen that 2 moles of water are produced for every 1 mole of ethylene glycol reacting with 1 mole of phthalic anhydride.
Difference between 0.1 M acetic acid and glacial acetic acid?
Glacial acetic acid doesn't have water in it. Acetic acid ordinarily would be in a solution. Acetic acid is a weak acid, but it can be very concentrated. Glacial acetic acid is a acetic acid of a high purity more then 99.75 %
How many grams of acetic acid would you use to make 10 liters of a 0.1 Mole aqueous solution of acetic acid?
C2H4O2 Find moles first. Molarity = moles of solute/Liters of solution moles C2H4O2 = molarity/Liters solution moles C2H4O2 = 0.1 M/10 L = 0.01 moles C2H4O2 -----------------------------------now, molar mass time moles 0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2) = 0.60 grams acetic acid needed --------------------------------------------
20 ml of acetic acid is titrated with a solution of 0.15 M NaOH If 35 ml of NaOH are required to reach the equivalence point what is the concentration of the acetic acid solution?
The moles of NaOH at the equivalence point will equal the moles of acetic acid present in the solution. Therefore, using the volume and concentration of NaOH used at the equivalence point, you can calculate the moles of NaOH used. Then, based on the stoichiometry of the reaction, you can determine the moles of acetic acid, and finally, determine the concentration of the acetic acid solution.
Which reagent is limiting cyclopentadiene or maleic anhydride?
To determine the limiting reagent, calculate the moles of each reactant using their respective masses and molar masses. Compare the moles of each reactant to the stoichiometry of the reaction. The reagent that produces the least amount of product based on stoichiometry is the limiting reagent.
How many moles of acetic acid C H3COOH a re contained within 21.71g of acetic acid?
Molar mass of ethanoic acid = (1x12) + (3x1) + (1x12) + (2x16) + (1x1) = 60 no. of moles = mass/ molar mass = 21.71/60 = 0.362 moles
How many moles of pottassium are represented by 9.27 x 1025?
The equivalent is 154 moles.
How many mL of 0.55 M NaOH would be required to reach the equivalence point for 25.0 mL of a 0.75 M solution of acetic acid?
To determine the volume of 0.55 M NaOH needed to reach the equivalence point with 25.0 mL of 0.75 M acetic acid, you need to use the stoichiometry of the reaction. Acetic acid reacts with NaOH in a 1:1 ratio, so moles of acetic acid equals moles of NaOH at the equivalence point. Calculate moles of acetic acid from its concentration and volume, equate it to moles of NaOH, and then calculate the volume of NaOH solution needed.
Aspirin is made by the reaction of salicylic acid with acetic an hydride what is the theoretical yield of aspirin if 85.0 grams of salicylic acid is treated with excess acetic an hydride?
Since salicylic acid is being reacted with excess acetic anhydride, salicylic acid is the limiting reactant of the reaction. The balanced equation of the reaction of salicylic acid and acetic anhydride indicates that their is a 1:1:1:1 ratio between every reactant and product. Based on this, it can be concluded that the moles of salicylic acid, if reacted entirely, will yield an equivalent amount of moles of aspirin. To find the theoretical yield, you must know the molecular weight of aspirin and salicylic acid. First, the amount of moles of salicylic acid must be calculated by dividing the gram amount of salicylic acid, which is 85 grams, and dividing it by its molecular weight, which is 138.12 grams per mole.85.0/138.12= 0.615 moles of salicylic acidThis is the mole amount of salicylic acid as well as the theoretical mole amount of aspirin. To convert the mole amount of aspirin into grams, this figure be multiplied by the molecular weight of aspirin, which is 180.15980.615 x 180.1598 = 111 grams of aspirin (when rounded to 3 significant figures)
