6.00ml * 1.08 = 6.48g
Molar mass acetic anhydride = 102.09 g/mol
6.48g = 6.48/102.09 = 0.063moles.
1. A lone pair on oxygen of water attacks a carbon in acetic anhydride, forcing one of the bonds in the carbonyl group (of acetic anhydride) to move onto its oxygen (oxygen of carbonyl group). The oxygen now has a negative charge and water is attached to the carbon that was once doubly bonded to oxygen. The water now has a positive charge, making it an oxonium ion. 2. The lone pair of electrons on the negatively charged oxygen (of the former carbonyl group) moves back down, forming a double bond again with carbon. 3. Carbon now has a negative charge so it has to get rid of it by breaking its bond with oxygen (the one in the middle of the anhydride). You now have 2 molecules. 4. The positive charge of water has to also go away so it loses a hydrogen. You now have one molecule of acetic acid. 5. The hydrogen attaches onto the oxygen that was broken away from carbon (but still attached to the carbonyl group of the other untouched carbon). And you now have your second molecule of acetic acid. So for every mole of acetic anhydride and water, you form 2 moles of acetic acid. It may be hard to understand this but i have a link for you if you are still confused.
.4118 mol ch3cooh
C2H4O2 Find moles first. Molarity = moles of solute/Liters of solution moles C2H4O2 = molarity/Liters solution moles C2H4O2 = 0.1 M/10 L = 0.01 moles C2H4O2 -----------------------------------now, molar mass time moles 0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2) = 0.60 grams acetic acid needed --------------------------------------------
780 moles
moles = mass / molar mass assuming that sulfur is simply represented by "S", then the molar mass is 32.07, as seen in the periodic table (meaning that each sulfur atom is 32.07 grams per mole. so moles of sulfur = 80.25 / 32.07 = 2.50 moles
0 moles
1. A lone pair on oxygen of water attacks a carbon in acetic anhydride, forcing one of the bonds in the carbonyl group (of acetic anhydride) to move onto its oxygen (oxygen of carbonyl group). The oxygen now has a negative charge and water is attached to the carbon that was once doubly bonded to oxygen. The water now has a positive charge, making it an oxonium ion. 2. The lone pair of electrons on the negatively charged oxygen (of the former carbonyl group) moves back down, forming a double bond again with carbon. 3. Carbon now has a negative charge so it has to get rid of it by breaking its bond with oxygen (the one in the middle of the anhydride). You now have 2 molecules. 4. The positive charge of water has to also go away so it loses a hydrogen. You now have one molecule of acetic acid. 5. The hydrogen attaches onto the oxygen that was broken away from carbon (but still attached to the carbonyl group of the other untouched carbon). And you now have your second molecule of acetic acid. So for every mole of acetic anhydride and water, you form 2 moles of acetic acid. It may be hard to understand this but i have a link for you if you are still confused.
.4118 mol ch3cooh
I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================
C2H4O2 Find moles first. Molarity = moles of solute/Liters of solution moles C2H4O2 = molarity/Liters solution moles C2H4O2 = 0.1 M/10 L = 0.01 moles C2H4O2 -----------------------------------now, molar mass time moles 0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2) = 0.60 grams acetic acid needed --------------------------------------------
Molar mass of ethanoic acid = (1x12) + (3x1) + (1x12) + (2x16) + (1x1) = 60 no. of moles = mass/ molar mass = 21.71/60 = 0.362 moles
The equivalent is 154 moles.
780 moles
Since salicylic acid is being reacted with excess acetic anhydride, salicylic acid is the limiting reactant of the reaction. The balanced equation of the reaction of salicylic acid and acetic anhydride indicates that their is a 1:1:1:1 ratio between every reactant and product. Based on this, it can be concluded that the moles of salicylic acid, if reacted entirely, will yield an equivalent amount of moles of aspirin. To find the theoretical yield, you must know the molecular weight of aspirin and salicylic acid. First, the amount of moles of salicylic acid must be calculated by dividing the gram amount of salicylic acid, which is 85 grams, and dividing it by its molecular weight, which is 138.12 grams per mole.85.0/138.12= 0.615 moles of salicylic acidThis is the mole amount of salicylic acid as well as the theoretical mole amount of aspirin. To convert the mole amount of aspirin into grams, this figure be multiplied by the molecular weight of aspirin, which is 180.15980.615 x 180.1598 = 111 grams of aspirin (when rounded to 3 significant figures)
This depends on the compound !
The number of moles is 0,528.
120