As stated in the electrical code, circuits are to be loaded to 80 percent of the total capacity when operating in a continuous state..
For a continuous load the circuit breaker is set 25% higher than the load current. So a 20-amp breaker is used with a continuous 16-amp load.
You should not exceed 80% of the breaker rating for a continuous load. Therefore, the continuous load should not exceed 16 amps.
A 225 amp load will physically not be able to tie into a 15 amp breaker and a duplex receptacle as you can not get a 3/0 wire under the breaker and receptacle terminal screws.
No, because if you switch a 50-amp load on, it will blow a 40-amp circuit breaker if the load exceeds 40 amps, which is likely.
If the load is continuous you need to observe 80% rule. A 20 Amp breaker will handle short term loads that exceed 16 Amps. Think about it as a heat issue where continuous higher current will heat up components to unacceptable levels.
For a continuous load the circuit breaker is set 25% higher than the load current. So a 20-amp breaker is used with a continuous 16-amp load.
You should not exceed 80% of the breaker rating for a continuous load. Therefore, the continuous load should not exceed 16 amps.
I would suggest a 20 amp breaker. * Added - I would suggest a 25 amp breaker. A slight surge, depending upon what equipment is the source of the 17.3 amp load, should not result in circuit breaker opening. <<>> In North America, the electrical code only allows circuit loading up to 80% on a continuous load. A 20 amp breaker can be legally loaded to 16 amps. A 25 amp breaker can be legally loaded to 20 amps.
The formula to use is I = W/E, assuming that the single breaker is delivering 120 volts, the amperage to the circuit is 16.6 amps. A continuous load on a 20 amp breaker has to be reduced to 80% according to the electrical code. 20 x .8 = 16. So to answer the question, yes, a 20 amp breaker will support a 2000 watt load at 120 volts.
A 225 amp load will physically not be able to tie into a 15 amp breaker and a duplex receptacle as you can not get a 3/0 wire under the breaker and receptacle terminal screws.
No, because if you switch a 50-amp load on, it will blow a 40-amp circuit breaker if the load exceeds 40 amps, which is likely.
If the load is continuous you need to observe 80% rule. A 20 Amp breaker will handle short term loads that exceed 16 Amps. Think about it as a heat issue where continuous higher current will heat up components to unacceptable levels.
Depends on what you have connected to the circuit. It is less than 10 amps or the breaker would trip. A rule of thumb is you design for about 80% load related to the breaker. For 20 amps that would equal 16 amps.
The formula you are looking for is I = W/E.
No, the 50 amp breaker should not be getting hot with a 17 amp load. Shut the service off at the disconnect and check the bolts that tighten the breaker to the distribution's bus bars. Check the tightness of the load side of the breaker. if all of these connections are tight then change the breaker out for a new one.
The appliance works perfectly. If you did it the other way around (50amps on a 30amp breaker, you would be tripping the breaker. Think of it as a mercury thermometer. The circuit breaker is the maximum temperature and the load on that breaker is the mercury. If the load is lower than the max, everything works beautifully. If the load becomes greater than the maximum rating, then things starting popping.
The maximum load on a 30 amp breaker is 30 amps at 40 degrees C. If the ambient temperature is higher that 40 degrees C then the breaker will trip at a lower current. Keep in mind the breaker is a dual function device. On a short circuit the magnetic component will trip the breaker instantaneously. If you are designing a branch circuit for a load that is constantly on, code may require you to "derate" the branch by 20 percent so that the ordinary load is not at the rated load of the overcurrent protection.