What you are talking about is the electrical potential, or voltage, necessary to produce a current of 4 amps through a material with a resistance of 3 ohms. The typical way to solve such a problem is by using Ohm's Law, stating that the current produced is proportional to the potential across the resistor but inversely proportional to the resistance. In other words, I = V / R, where I is the current in amps, V is the electrical potential in volts, and R is the resistance in ohms. Here we know R and I, so we rearrange this equation to get V by itself: V = I * R. So, to get the answer, multiply your 4-amp current by your 3-ohm resistance, and you will get 12 volts.
Ohm's Law states that Voltage = Current x Resistance. 8/4 = 2 amps.
answer will be 40 as we know V=IR {OHMS LAW} AND WE ARE GIVEN I=4 AND R=10 THEREFORE VOLTAGE =40 VOLTS
16 volts
12 Volts
Voltage = Current x Resistance giving us Current = Voltage / Resistance i.e. Voltage divided by resistance
Current, voltage and resistance are related by the Ohm's law formula which states that current is directly proportional to the applied voltage and inversely proportional to the resistance at a constant temperature. Stated mathematically: I = E/R where I = current in amperes, abbreviated to A E = voltage in volts, abbreviated to V R = resistance in ohms, usually signified by the Greek omega Ω
If resistance increases and voltage stays the same, then current decreases. Ohm's Law: Current equals Voltage divided by Resistance.
the current doubles.. explanation:V=IR hence I=V/R which means that when the supply voltage is constant ,current is inversely proportional to resistance.thus the current doubles. practically speaking when the resistance of the load(fan ,bulb,refrigerator,....) is less ,it draws more current from the source so as to balance the voltage across it.i.e; to maintain the voltage across it as constant. This answer is absolutely correct if you assume that the current comes from a pure voltage source ( voltage source with zero internal resistance). At the other extreme you could have a current source (such as a very large voltage source in series with a very large resistor), and then the current is practically independent of changes if the external resistance is changed (because the change represents a relatively minute change in the overall resistance). With appropriate circuitry it is possible to devise a situation where the current is practically independent of the changing resistance.
It is halved. coz voltage=current * resistance
ohms law calculation for a series circuit - Total Resistance = Total Voltage divided by Total Current
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
There are various formula of load calculation. Power equals current multiplied by the voltage. Power can also be computed by multiplying the resistance by the square of the current.
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = Current x Resistance giving us Current = Voltage / Resistance i.e. Voltage divided by resistance
They are the three components that are used in Ohms law. Knowing any two will lead to the calculation of the third.
No. Voltage divided by resistance is equal to current.
Voltage = Current * Resistance (Ohm's law)
Ohm's Law: voltage = current * resistance. If resistance is a constant, then voltage is directly proportional to current.
Ohm's Law Voltage = Current x Resistance Current = Voltage divided by Resistance Resistance = Voltage divided by Current
Current, voltage and resistance are related by the Ohm's law formula which states that current is directly proportional to the applied voltage and inversely proportional to the resistance at a constant temperature. Stated mathematically: I = E/R where I = current in amperes, abbreviated to A E = voltage in volts, abbreviated to V R = resistance in ohms, usually signified by the Greek omega Ω