10dB It is a logarithmic relationship, so a gain of 20 is 13dB, and a gain of 100 is 20dB
Deci-bels (dB) are a logarithmic measure of system/network amplification or gain (G). The logarithms are taken to the base 10 and multiplied by 20:dB = 20logG (where G is the gain of the system)To give an example of what this means:G = 0.01, so dB gain = 20log0.01 = 20 * -2 = -40dBG = 0.1, so dB gain = 20log0.1 = 20 * -1 = -20dBG = 1, so dB gain = 20log1 = 20 * 0 = 0dBG = 10, so dB gain = 20log10 = 20 * 1 = 20dBG = 100, so dB gain = 20log100 = 20 * 2 = 40dBG = 10000, so dB gain = 20log10000 = 20 * 4 = 80dBThere are other uses for dB in electronics, where logarithms are useful they are preferred. The reasons logs can be useful is because the natural log of an exponential curve is a straight line, allowing for easier ways of understanding the behaviour of a system.
The voltage gain of an amplifier is 200. The decibel voltage gain is? Answer Gain in dB = 20 * log 200 = 46 dB
The 3 dB point belongs to the cutoff frequency or the corner frequency. There the 100 % voltage is then down to 70,7 % and the power is down to 50% at the same time.
If you want to work in watts, convert 25dB to a scalling factor: 3dB = 2 x input 10dB = 10 x input 20dB = 100 x input ...25dB = 10 ^ (25/10) = 316.2 x input So the output is 15 micro Watts x 316.2 = (4700)/(10^6) = 4.7 milli watts If you want to work in dB, then convert 15 micro watts to dB: 10 * log |P| = dB = 10*log |15 x 10^6| = -48.2dB ***When you have very small (ie negative) dB, it is often referred to in dBm, or 1/1000 of dB ( 30 dBm = 0 dB) so the output is -18.2dBm + 25 = 6.8dBm, or -23.2dB
In power wattage increases by two times for every three DBs of increase. A starting point is needed to do this calculation. The equation you're looking for is 10*log |P| = P in dB for example, 0 dB = 1 watt 10 dB = 10 watts for 13.936dB, 10^1.3936 = 24.75 watts.
10 dB gain means a voltage ratio of 3.16227766 to 1.
Deci-bels (dB) are a logarithmic measure of system/network amplification or gain (G). The logarithms are taken to the base 10 and multiplied by 20:dB = 20logG (where G is the gain of the system)To give an example of what this means:G = 0.01, so dB gain = 20log0.01 = 20 * -2 = -40dBG = 0.1, so dB gain = 20log0.1 = 20 * -1 = -20dBG = 1, so dB gain = 20log1 = 20 * 0 = 0dBG = 10, so dB gain = 20log10 = 20 * 1 = 20dBG = 100, so dB gain = 20log100 = 20 * 2 = 40dBG = 10000, so dB gain = 20log10000 = 20 * 4 = 80dBThere are other uses for dB in electronics, where logarithms are useful they are preferred. The reasons logs can be useful is because the natural log of an exponential curve is a straight line, allowing for easier ways of understanding the behaviour of a system.
A decibel (dB) has meaning only when compared a quantity (P1, V1, or I1) with a reference (P0, V0, or I0). Since it is a ratio of two like quantities, it is dimensionless. For a power ratio, power gain = 10 * log10(P1/Po) in [dB]. For a voltage ratio, voltage gain = 20 * log10(V1/Vo) in [dB]. For example, when P1 = 100 * P0, the power gain = 10 * log10(100) [dB] = 20 dB.
You must find a resistance value for 0 dB as reference. If 1 Ohm = 0 dB then 10 ohms = 20 dB and 100 ohms = 40 dB.
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using bode-m plots , one can tranfer dB magnitude to gain and gain to frequency
No, it is 10 times louder. dB is a logarithmic scale; every 10 dB, the intensity increases by a factor of 10. Thus, 10 dB is 10 times louder than 0 dB, 20 dB is 10 times louder than 10 dB, and 30 dB is 10 times louder than 20 dB.No, it is 10 times louder. dB is a logarithmic scale; every 10 dB, the intensity increases by a factor of 10. Thus, 10 dB is 10 times louder than 0 dB, 20 dB is 10 times louder than 10 dB, and 30 dB is 10 times louder than 20 dB.No, it is 10 times louder. dB is a logarithmic scale; every 10 dB, the intensity increases by a factor of 10. Thus, 10 dB is 10 times louder than 0 dB, 20 dB is 10 times louder than 10 dB, and 30 dB is 10 times louder than 20 dB.No, it is 10 times louder. dB is a logarithmic scale; every 10 dB, the intensity increases by a factor of 10. Thus, 10 dB is 10 times louder than 0 dB, 20 dB is 10 times louder than 10 dB, and 30 dB is 10 times louder than 20 dB.
The voltage gain of an amplifier is 200. The decibel voltage gain is? Answer Gain in dB = 20 * log 200 = 46 dB
db gain is defined as power gain, not voltage gain. Please restate you question in terms of power, or provide details of input and output impedance.
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If you're doing anything with amplifier circuits, you really need to understand dB and be able to calculate it on your own. Here is everything you need to know about dB: The definition. Please memorize this: dB gain = 10 log [ (final power) divided by (original power) ] In your example: Original power = 375 mW = 0.375 W Final power = 1.79 W (final) / (original) = ( 1.79 / 0.375 ) = 4.7733 log ( 4.7733 ) = 0.678 Gain = 10 times the log = 6.78 dB
dB (decibel) is a logarithmic measure of the ratio of two power values, for example, two signal strengths. This is often used for power gain or power loss. For example, a loss of 10 dB means that the signal degrades by a factor of 10, a loss of 20 dB means that the signal degrades by a factor of 100, and a loss of 30 dB means that the signal degrades by a factor of 1000.