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their isn't one
CuSO4 is an anhydrous salt which will absorb water so the way to find out how much is in it is to find out the difference in water befor and after addition and calculate it by finding the mols of water absorbed incomplarison with the number of mols of CuSO4 used.
it is normally wrighten nH2O. CuSO4
What else can I help you with?
What is a balanced equation for the decomposition of copper sulfate pentahydrate?
CuSO4•5H2O + heat ---> CuSO4 + 5H2O
What is the reaction CuSO4 5H2o plus heat?
CuSO4 * 5H2O ----> CuSO4 + 5H2O. This is true because CuSO4 * 5 H2O is a salt weakly bounded to water, that is why it is hydrous. When it decomposes, the weak bonds are broken making the products above. CuSO4*5H2O formula is [Cu(OH2)4]SO4*H2O CuSO4 + 5H2O --> [Cu(OH2)4]SO4*H2O
What is a balanced chemical equation for the decomposition of copper 2 sulfate pentahydrate?
The balanced chemical equation for the decomposition of copper (II) sulfate pentahydrate ((CuSO_4 \cdot 5H_2O)) is: [CuSO_4 \cdot 5H_2O \rightarrow CuSO_4 + 5H_2O] This equation represents the decomposition of copper (II) sulfate pentahydrate into copper (II) sulfate and water. The balanced equation shows that one mole of copper (II) sulfate pentahydrate decomposes into one mole of copper (II) sulfate and five moles of water.
What happens when you heat hydrated copper sulfate?
When you heat hydrated copper sulfate (CuSO4•5H2O), the water molecules in the crystal structure are driven off, leaving anhydrous copper sulfate (CuSO4) behind. The color of the compound changes from blue to white as it loses its water molecules.
How many grams of copper sulfate would you heat to produce 29.8g of water?
Well, darling, to produce 29.8g of water, you'd need to heat 249.9g of copper sulfate pentahydrate. When you heat it, the water molecules will be driven off, leaving you with just the copper sulfate. Just make sure to wear your safety goggles, we don't need any accidents in the name of science!
What is a balanced equation for the decomposition of copper sulfate pentahydrate?
CuSO4•5H2O + heat ---> CuSO4 + 5H2O
What is the balanced equation when copper ll sulfate pentahydrate is heated?
The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.
How many grams of copper sulfate pentahydrate CuSO4 5H2O would you heat to produce 29.8 g of water?
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
What is the reaction CuSO4 5H2o plus heat?
CuSO4 * 5H2O ----> CuSO4 + 5H2O. This is true because CuSO4 * 5 H2O is a salt weakly bounded to water, that is why it is hydrous. When it decomposes, the weak bonds are broken making the products above. CuSO4*5H2O formula is [Cu(OH2)4]SO4*H2O CuSO4 + 5H2O --> [Cu(OH2)4]SO4*H2O
Balance Copper 2 sulfate pentahydrate is heated to drive off the water hydration?
When heating copper(II) sulfate pentahydrate, the water molecules in the crystal structure are removed, leaving anhydrous copper(II) sulfate. The balanced chemical equation for this reaction is CuSO4·5H2O(s) → CuSO4(s) + 5H2O(g).
What is a balanced chemical equation for the decomposition of copper 2 sulfate pentahydrate?
The balanced chemical equation for the decomposition of copper (II) sulfate pentahydrate ((CuSO_4 \cdot 5H_2O)) is: [CuSO_4 \cdot 5H_2O \rightarrow CuSO_4 + 5H_2O] This equation represents the decomposition of copper (II) sulfate pentahydrate into copper (II) sulfate and water. The balanced equation shows that one mole of copper (II) sulfate pentahydrate decomposes into one mole of copper (II) sulfate and five moles of water.
What happens when you heat hydrated copper sulfate?
When you heat hydrated copper sulfate (CuSO4•5H2O), the water molecules in the crystal structure are driven off, leaving anhydrous copper sulfate (CuSO4) behind. The color of the compound changes from blue to white as it loses its water molecules.
How many grams of copper sulfate would you heat to produce 29.8g of water?
Well, darling, to produce 29.8g of water, you'd need to heat 249.9g of copper sulfate pentahydrate. When you heat it, the water molecules will be driven off, leaving you with just the copper sulfate. Just make sure to wear your safety goggles, we don't need any accidents in the name of science!
What is the chemical equation for he reaction of copper sulfate when heated?
When you heat copper(II)sulfate pentahydrate (a blue compound), you dehydrate the compound, which means you remove the water. The dehydrated compound is white. You can add water to this to rehydrate the compound, and turn it back to blue. The equation for the dehydration of copper(II)sulfate is: CuSO4o5H2O --> CuSO4 + 5H2O On the reactant side the copper(II)sulfate is chemically bonded to the 5 water molecules. On the product side, the water is no longer bonded. (You should be able to see it on the mouth of the test tube if you heat the substance in a test tuve under a Bunsen burner)
What is the chemical equation for the dehydration of magnesium sulfate?
The chemical equation for the dehydration of magnesium sulfate (MgSO4) is as follows: MgSO4·7H2O + Heat => MgSO4 + 7H2O A link is provided below for more information.
What equation show the balanced combustion reaction for isobutane?
C4H10 + 6.5O2 4CO2 + 5H2O + heat
Why do you get drunk faster in a hot tub?
Heat and dehydration. You risk heat stroke and death.
