Not enough information. To get the density, you need to divide the mass by the volume, but there is no way of knowing the volume of an object just by having one of its lengths.
0.032g/mls
That depends on the position and focal length of the optical elements forming the image.
p = m/V 11.342g/mL = 200g/V V = 200g / 11.342g/mL V = 17.63 mL
An eye works by taking the light that is coming from a point on an object and bending it so that it is all focused on single point at the back of the eye. The lens of the eye can only bend the light so much and the closer the object is the more the eye has to bend the light. If the object is closer than 25 cm it can't bend it enough.
We know that the density of gold = m/v the volume is given in cm, so you have to convert each value into meters so you have .6m X .25m X .15m the density of gold is 19.3 x103 KG mass = density X volume mass = 19.3 x 103(.6 x .25 x .15) mass = 434.25 kg
Imagine three glass tubes with equal cross-section of 1 square cm and of length 100 cm each. Fill the first tube with water to the 75cm mark, the second to the 50cm mark and the third to the 25cm mark. The density of water would be one of the following 1) Mass of the 75cm column with a cross section of 1 sq cm divided by 75 cubic cm 2) Mass of the 50cm column with a cross section of 1 sq cm divided by 50 cubic cm 3) Mass of the 25cm column with a cross section of 1 sq cm divided by 25 cubic cm and in each case should give you an answer close to 1 gm per cubic cm. Thus the density stays the same no matter how high the water is in each tube. On the other hand the pressure at the bottom of each tube is different and is the force exerted per unit area by the column of water in each tube which are again different. We have conveniently selected tubes with 1 sq cm (unit area in CGS system) cross sectional areas. So the weight of the column in each tube would be the pressure. Hence the pressure in the first tube would be 1) Weight of the 75cm water column = 75 x 1 x g = 75g dynes 2) Weight of the 50cm water column = 50 x 1 x g = 50g dynes 3) Weight of the 25cm water column = 25 x 1 x g = 25g dynes Thus density remains the same for a given temperature and pressure but the pressure depends on the weight the column of liquid per unit area.
You would have to know the density also. Mass = volume X density
The object has a density of 0.32 g/cm3
Volume = length*width*height, which for the 25cm cube are all 25 cm. Vol = 25cm * 25cm * 25cm = 15625 cubic cm = 15.625 cubic decimetres = 15.625 litres.
Density is defined as mass divided by volume, therefore: 100g/25cm3 = 4 g/cm3
The volume is 15,600 cm3
The volume of a sphere with a diameter of 25cm is about 8181.2cm3
The volume of the gold bar is not affected by such a physical deformation and remains at 525 cm3 and so the density is unchanged.
A cube which has edges 25cm long has a volume of 25 cubed cubic centimetres = 25 x 25 x 25= 15625 cubic centimetres (cc) =15.625 litres
volume = depth x length x width or volume = depth x area Your area is 1m² and your depth is 25cm or 0.25 m so.... Volume = .25m x 1m² = .25 m³
It is: 25 cm to 1 meter = 25/100 or 1 to 4
The length of the third side is 20 cm
That depends on the position and focal length of the optical elements forming the image.