This question needs additional information to enable me correctly answer it.
46.2kg
whose resistance=0,inductance=0
3ohm
Solid? or Hollow?
A pendulum whose period is precisely two seconds, one second for a swing forward and one second for a swing back, has a length of 0.994 m or 39.1 inches.
I get 9
The length of the diameter of a circle whose circumference is 62.8 is about 20 units (19.99). (d = c divided by Pi)
1
It is 14.00281721 or about 14 cm
Radius = 1/2 diameter Radius = 7.5 ft = 7ft 6inches.
the chord is 4in long
That would be a piece of threaded pipe whose length is 2 to 3 times the diameter of the pipe.
46.2kg
Points: (-5, 4) and (3, -6) Length: (-5-3)2+(4--6)2 = 164 and the square root of this is the diameter
If by length you mean diameter then the surface area is 80π cm squared= about 251.327cm squared
10mm ms rod for waight
The circumference of circle whose diameter is 10 is: 31.42 (diameter x Pi = circumference).