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The product of the units Atomic Mass (g/mol), Avogadro's number(mol/atom), 1/density (m^3/kg) and, 1(kg/g) yield the volume of a copper atom. (63.5*(1/6.022E23)/(8930*1000)= 1.12E-23m^3. The volume of a sphere is given as 4(pi)(r^3)/3. Solving for r: r=(3*1.12E-23/(4pi))^(1/3)=1.41E-10m. Multiplying by 2, d = 2.42E-10m.

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Q: What is the diameter of a copper atom with atomic mass is 63.5 and density is 8.93ESP3 kgm-3?
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