plz tell me rite answer??
Capacitance is defined as the maximum charge stored in a capacitor per unit potential difference. According to this definition, the formula should be : Capacitance = Charge stored / Potential Difference
Mechanical Advantage is given by the following equation: MA = Load Effort On a class 2 lever, the fulcrum (pivot) is at one end of the lever and the work applied is at the other end. The load is then applied near the fulcrum, as common with the wheel barrow. A class 3 lever has the effort applied between the fulcrum and the resistance. Therefore, a much greater effort will be required to produce the same moment value. A typical C2 lever has a much greater distance in which to produce the load than a C3 lever.
See: http://en.wikipedia.org/wiki/M%C3%B6ssbauer_effect
The following rules apply to a parallel circuit:The potential drops of each branch equals the potential rise of the source.The total current is equal to the sum of the currents in the branches.The inverse of the total resistance of the circuit (also called effective resistance) is equal to the sum of the inverses of the individual resistances.One important thing to notice from this last equation is that the more branches you add to a parallel circuit (the more things you plug in) the lower the total resistance becomes. Remember that as the total resistance decreases, the total current increases. So, the more things you plug in, the more current has to flow through the wiring in the wall. That's why plugging too many things in to one electrical outlet can create a real fire hazard.
#include<iostream.h> #include<conio.h> class complex { int a,b; public: void read() { cout<<"\n\nEnter the REAL PART : "; cin>>a; cout<<"\n\nEnter the IMAGINARY PART : "; cin>>b; } complex operator +(complex c2) { complex c3; c3.a=a+c2.a; c3.b=b+c2.b; return c3; } complex operator -(complex c2) { complex c3; c3.a=a-c2.a; c3.b=b-c2.b; return c3; } complex operator *(complex c2) { complex c3; c3.a=(a*c2.a)-(b*c2.b); c3.b=(b*c2.a)+(a*c2.b); return c3; } complex operator /(complex c2) { complex c3; c3.a=((a*c2.a)+(b*c2.b))/((c2.a*c2.a)+(c2.b*c2.b)); c3.b=((b*c2.a)-(a*c2.b))/((c2.a*c2.a)+(c2.b*c2.b)); return c3; } void display() { cout<<a<<"+"<<b<<"i"; } }; void main() { complex c1,c2,c3; int choice,cont; do { clrscr(); cout<<"\t\tCOMPLEX NUMBERS\n\n1.ADDITION\n\n2.SUBTRACTION\n\n3.MULTIPLICATION\n\n4.DIVISION"; cout<<"\n\nEnter your choice : "; cin>>choice; if(choice==1choice==2choice==3choice==4) { cout<<"\n\nEnter the First Complex Number"; c1.read(); cout<<"\n\nEnter the Second Complex Number"; c2.read(); } switch(choice) { case 1 : c3=c1+c2; cout<<"\n\nSUM = "; c3.display(); break; case 2 : c3=c1-c2; cout<<"\n\nResult = "; c3.display(); break; case 3 : c3=c1*c2; cout<<"\n\nPRODUCT = "; c3.display(); break; case 4 : c3=c1/c2; cout<<"\n\nQOUTIENT = "; c3.display(); break; default : cout<<"\n\nUndefined Choice"; } cout<<"\n\nDo You Want to Continue?(1-Y,0-N)"; cin>>cont; }while(cont==1); getch(); }
Butyne has 4 carbons and a triple bond. The triple bond can be between C1 and C2, or C2 and C3 so there are 2 different "forms" or isomers of butyne.
fracture in c2 c3 neck
If that's + c3, the answer is c(c - 1)(c + 1)(c + 1)
Convert all your capacitances to their equivalent impedance, then use Y-Delta Conversion formulae. Impedances mix and match like resistances. If the resistor version is: (Y to delta) Ra = (R1*R2 + R2*R3 + R3*R1)/R2 Rb = (R1*R2 + R2*R3 + R3*R1)/R3 Rc = (R1*R2 + R2*R3 + R3*R1)/R1 Then the capacitor version looks like: Ca = C1*C3/(C1 + C2 + C3) Cb = C1*C2/(C1 + C2 + C3) Cc = C2*C3/(C1 + C2 + C3)
This typically indicates that there is no obvious compression or narrowing of the central canal or neural foramen at the C2-C3 level of the spine. "Patent" means that these spaces are open and unobstructed. It suggests there are no significant structural abnormalities in this area.
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The simplest way is as follows: =B2+C3
No, the WhatsApp cannot be used on the Nokia C2-02. The only Nokia Phones that it is compatible with are the C3-00, C3-01, X2-01, X3-02, X3-02.5, and some of the Nokia Asha phones.
No, the WhatsApp cannot be used on the Nokia C2-02. The only Nokia Phones that it is compatible with are the C3-00, C3-01, X2-01, X3-02, X3-02.5, and some of the Nokia Asha phones.
C2 pathway is photo respiratory pathway where oxygen is fixed by RuBisCo instead of CO2( asin normal photosynthetic plants or C3 plants)