privacy, authenticity, integrity, trust
Convert all your capacitances to their equivalent impedance, then use Y-Delta Conversion formulae. Impedances mix and match like resistances. If the resistor version is: (Y to delta) Ra = (R1*R2 + R2*R3 + R3*R1)/R2 Rb = (R1*R2 + R2*R3 + R3*R1)/R3 Rc = (R1*R2 + R2*R3 + R3*R1)/R1 Then the capacitor version looks like: Ca = C1*C3/(C1 + C2 + C3) Cb = C1*C2/(C1 + C2 + C3) Cc = C2*C3/(C1 + C2 + C3)
#include<iostream.h> #include<conio.h> class complex { int a,b; public: void read() { cout<<"\n\nEnter the REAL PART : "; cin>>a; cout<<"\n\nEnter the IMAGINARY PART : "; cin>>b; } complex operator +(complex c2) { complex c3; c3.a=a+c2.a; c3.b=b+c2.b; return c3; } complex operator -(complex c2) { complex c3; c3.a=a-c2.a; c3.b=b-c2.b; return c3; } complex operator *(complex c2) { complex c3; c3.a=(a*c2.a)-(b*c2.b); c3.b=(b*c2.a)+(a*c2.b); return c3; } complex operator /(complex c2) { complex c3; c3.a=((a*c2.a)+(b*c2.b))/((c2.a*c2.a)+(c2.b*c2.b)); c3.b=((b*c2.a)-(a*c2.b))/((c2.a*c2.a)+(c2.b*c2.b)); return c3; } void display() { cout<<a<<"+"<<b<<"i"; } }; void main() { complex c1,c2,c3; int choice,cont; do { clrscr(); cout<<"\t\tCOMPLEX NUMBERS\n\n1.ADDITION\n\n2.SUBTRACTION\n\n3.MULTIPLICATION\n\n4.DIVISION"; cout<<"\n\nEnter your choice : "; cin>>choice; if(choice==1choice==2choice==3choice==4) { cout<<"\n\nEnter the First Complex Number"; c1.read(); cout<<"\n\nEnter the Second Complex Number"; c2.read(); } switch(choice) { case 1 : c3=c1+c2; cout<<"\n\nSUM = "; c3.display(); break; case 2 : c3=c1-c2; cout<<"\n\nResult = "; c3.display(); break; case 3 : c3=c1*c2; cout<<"\n\nPRODUCT = "; c3.display(); break; case 4 : c3=c1/c2; cout<<"\n\nQOUTIENT = "; c3.display(); break; default : cout<<"\n\nUndefined Choice"; } cout<<"\n\nDo You Want to Continue?(1-Y,0-N)"; cin>>cont; }while(cont==1); getch(); }
capacitance C=C1+C2+C3
Butyne has 4 carbons and a triple bond. The triple bond can be between C1 and C2, or C2 and C3 so there are 2 different "forms" or isomers of butyne.
3 Missionaries: M1, M2, M3 3 Cannibals: C1, C2, C3 Start Shore A Other Shore B 1. C1, M1 take the boat and cross the river and C1 stays on shore B, M1 comes back to shore A. 2. C2, C3 take the boat and cross the river and C2 stays on shore B, C3 comes back to shore A ( C1, C2 on Shore B). 3. M1, M2 take the boat and cross the river and M1 stays on shore B, M2,C2 come back to shore A (M1, C1 on shore B). 4. M2, M3 take the boat and cross the river and M2, M3 stays on shore B, C1 comes back to shore A (M1, M2, M3 on shore B). 5. C1, C2 take the boat and cross the river and C1 gets off and C2 goes back to shore A and brings C3. All lived happily ever after.
There are only 2 cervical vertebrae that have common names: the atlas and the axis, they act as the pivot that allows you to turn your head.
#include<iostream.h> #include<conio.h> class complex { int r; int i; public: complex() { } complex(int a,int b) { r=a;i=b; } friend complex operator+(complex,complex); friend show(complex); complex operator+(complex c1,complex c2) { complex c3; c3.r=c1.r+c2.r; c3.i=c1.i+c2.i; return(c3); } show(complex c) { cout<<c.r<<"i+"<<c.i<<endl; } void main() { complex a,b,c; clrscr(); a.complex(3,6); b.complex(4,7); c=a+b; show(a); show(b); show(c); getch() }
Capacitance is defined as the maximum charge stored in a capacitor per unit potential difference. According to this definition, the formula should be : Capacitance = Charge stored / Potential Difference
The primacy index can be calculated by the following formula: PI = C1/ (C1 + C2 + C3 + C4) * 100 PI = primacy index C1 = amount of people in the biggest city of the country C2 = amount of people in the second city of the country C3 = amount of people on the third city of the country C4 = amount of people in the fourth city of the country So you divide the population of the biggest city of the country by the sum of the four biggest cities in the country and multiply that by 100. If the PI is > or = to 50, then it is a primate city.
an FIR filter has linear phase characteristic, if coefficient symmetry (or antisymmetry) with respect to h(N/2) applies. ex: h(n)={c0,c1,c2,c3,c4,c5,c6}, then the corresponding FIR filter would have linear response if: c0=c6, c1=c5, c2=c4.
If the matrix is { a1 b1 c1} {a2 b2 c2} {a3 b3 c3} then the determinant is a1b2c3 + b1c2a3 + c1a2b3 - (c1b2a3 + a1c2b3 + b1a2c3)
=IF(OR(C1>100,C2>100,C3>100),"Oops!","Looks Good")Syntax is: OR(condition1,condition2,...)condition = Something you want to test that can either be TRUE or FALSE. You can have up to 30 conditions.