A std::string is an object that encapsulates an array of type char whereas a C-style string is a primitive array with no members. A std::string is guaranteed to be null-terminated but a C-style string is not.
std::string::substr();
There are no such terms in C++.
To change any string to uppercase, loop through each character in the string. If the character is in the range 'a' through 'z', decrement the character by decimal 32 (the difference between ASCII value 'a' and 'A'). The following function shows an example of this: void to_upper(std::string& str) { for(int i=0; i<str.size(); ++i) if(str[i]>='a' && str[i]<='z') str[i]-=32; }
There is no such thing as devoid in C++.
Both ++you and you++ have the same ending result. The variable you is incremented. The difference is that, if you use the combination in a larger expression, then you++ will have the initial value of you, while ++you has the incremented value of you.
The plus operator between string constants allows string concatination: string a = "Hello, "; string b = "World!"; string c = a + b; The output of c would be: "Hello, World!".
The \n escape sequence simply inserts a newline within a string. std:endl does the same but also flushes the write buffer.
What is the difference between private stafford and plus student loans?
std::string::substr();
Nothing.
There are no such terms in C++.
To change any string to uppercase, loop through each character in the string. If the character is in the range 'a' through 'z', decrement the character by decimal 32 (the difference between ASCII value 'a' and 'A'). The following function shows an example of this: void to_upper(std::string& str) { for(int i=0; i<str.size(); ++i) if(str[i]>='a' && str[i]<='z') str[i]-=32; }
There is no difference. Both statements are invalid.
They have different names
-4
rightable and rewightable
There is no such thing as devoid in C++.