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If the period is ' t ', then the frequency is 1/t .
Look at the formula for the kinetic energy of an object: KE = 1/2 M V2Did you notice that " V2 " ? That means the KE is proportional to the squareof the object's velocity.So if the object's speed doubles, its KE increases by (2)2 = a factor of 4.
PE in physics is Potential Energy which means: energy an object has because of the position, shape, or condition of the object. KE in physics is Kinetic Energy which means: the energy of an object that is due to the object's motion.
In the case of a falling object, the instant before the object hits the ground. U = KE + PE; PE=-KE . Inversely, the object has the highest potential energy (lowest kinetic energy) at the starting point of the fall.
Correct.
If the period is ' t ', then the frequency is 1/t .
The first object loses KE and the second gains KE.
A moving object has kinetic energy, KE, equal to 1/2 times its mass m times its velocity squared ,v^2 which is written: KE = (1/2)mv^2 since you know KE and v you can then solve for m.
Look at the formula for the kinetic energy of an object: KE = 1/2 M V2Did you notice that " V2 " ? That means the KE is proportional to the squareof the object's velocity.So if the object's speed doubles, its KE increases by (2)2 = a factor of 4.
PE in physics is Potential Energy which means: energy an object has because of the position, shape, or condition of the object. KE in physics is Kinetic Energy which means: the energy of an object that is due to the object's motion.
an object can have a non zero force acting upon it if and only if the sum of all of the forces on the object is still equal to zero. The sum of the forces is equal to mass times acceleration. If an object is accelerating, then it does not have a constant KE therefore the sum of the forces must be equal to 0 so that acceleration is also equal to zero. For instance, take the case of an object falling through the air. Initially, the force of gravity is accelerating the object downward and it is gaining KE. After some time, this object will reach terminal velocity. At this point, the resistance force of the air on the object negates the force of gravity and the sum of the forces is equal to zero. The object now falls at a constant velocity and in turn also a constant KE. It is still being acted upon by the force of gravity and the resistance force but these forces are canceling each other out. =============================== I don't like to delete an answer that somebody put a lot of effort into, and supervisors don't like it when I become plainly uncomplimentary. So all I can say is: Use the above answer at your own extreme peril, and far better to ignore it. Especially the 1st and 3rd sentences.
In the case of a falling object, the instant before the object hits the ground. U = KE + PE; PE=-KE . Inversely, the object has the highest potential energy (lowest kinetic energy) at the starting point of the fall.
Correct.
You can derive it from accelerating an object to a certain speed. Assume constant acceleration (and therefore constant force), and calculate how much work (force x distance) you need to get the object to a specific speed.
KE = mv2 The mass and the squared velocity of the object.
Moving of an object releas the p.e due to aac.
Kinetic energy = 1/2 (Mass) (Velocity)2. Since KE is proportional to V2, doubling the velocity increases KE by 22 = a factor of 4.