In case of feely falling body
distance = 1/2 acceleration x time squared; acceleration is 7 m/s/s
If the 'weight' of a body is the gravitational force between the body and the Earth, then as long as the body stays at about the same distance from the center of the Earth, its weight is constant, and has no connection with its motion.
A falling body initially falls at a rate of -9.8m/s2, the acceleration due to gravity. Because of the drag force of the air, which is an upward force that opposes the force of gravity, the body's acceleration will decrease as it continues falling. When the drag force equals the weight of the falling body, there will be no further acceleration, and the body will have reached terminal velocity.
if body is free falling state its acceleration would be 9.8meter/second2
acceleration of a falling body is 9.8m/s*s and its direction is vertically downward.
Seconds times seconds -- for example, the acceleration of a falling body in the earth's gravitational field is equal to 9.8 metres per second squared, so if a body has been falling for 5 seconds, the equation reads 9.8M x 5 x 5
heres the average 2.2 seconds
In case of feely falling body
If air resistance can be ignored, the distance in meters is 4.9t2. Note that 4.9 is half the numerical value of Earth's acceleration (9.8 meters per second square).
a nswer
distance = 1/2 acceleration x time squared; acceleration is 7 m/s/s
If the 'weight' of a body is the gravitational force between the body and the Earth, then as long as the body stays at about the same distance from the center of the Earth, its weight is constant, and has no connection with its motion.
according to Newton"s third law,the force on a falling body is equal to the force exerted by the earth on the body which is given as the product of mass of the body and acceleration due to gravity,ie, F=mg (g=9.8 m per seconds sq.)
Time to hit bottom of a cliffIf you ignore the air resistance, any falling body will accelerate at the same constant rate under the action of gravity. On the earth, the accelaration of the gravity is about 9.81 m/s2 (9.81 meter per second squared). This is to say that the speed of the falling body will increase by 9.81 m/s, every second.For a body accelerating from rest, the distance travelled and the time elapsed are related by the equation:D = (a*t2)/2where 'D' is the distance, 'a' the acceleration and 't' the time. Furthermore, the velocity 'V' of the body after 't' seconds under the same acceleration will be:V = a*tUsing these two relations, one can easily determine that a body falling from the top of a cliff 50 meters high will hit the bottom in about 3.19 seconds, at a speed of approximately 31.3 m/s (which is about 112,8 km/h or 67.7 mph).
food travels in our body in a form of liquid after they are digested
Hormones, or chemical messenger, is introduced into the blood or lympathic system then travels to other parts of the body.