No.
The effect of diode voltage drop as the output voltage is that the input voltage will not be totally transferred to the output because power loss in the diode . The output voltage will then be given by: vout=(vin)-(the diode voltage drop).
Because the windings of transformers have resistance, the primary and secondary currents will cause voltage drops. To compensate for the drops, the transformer may have been designed to have a higher than specified output voltage when there is little or no output current. The no load output voltage typically is only slightly greater than the specified voltage. Before measuring the output voltage, measure the input (line) voltage. If it is not as specified for the transformer, calculate its effect on the output.
Output voltage (...of a transformer, for example...) will decrease as it is loaded because of the transformer's internal resistance. As output current increases/load resistance decreases, a larger voltage will be dropped across the internal transformer resistance. This same phenomenon is present in AC and DC systems (such as batteries).
It does :)
The frequency would decrease the gain and increase the output voltage
output resistance decreases and input resistance increases
The effect of diode voltage drop as the output voltage is that the input voltage will not be totally transferred to the output because power loss in the diode . The output voltage will then be given by: vout=(vin)-(the diode voltage drop).
A light doesn't output current, it "draws" current based on voltage and its resistance. Voltage = Current x Resistance or Current = Voltage / Resistance. (Ohm's Law)
Because the windings of transformers have resistance, the primary and secondary currents will cause voltage drops. To compensate for the drops, the transformer may have been designed to have a higher than specified output voltage when there is little or no output current. The no load output voltage typically is only slightly greater than the specified voltage. Before measuring the output voltage, measure the input (line) voltage. If it is not as specified for the transformer, calculate its effect on the output.
Output voltage (...of a transformer, for example...) will decrease as it is loaded because of the transformer's internal resistance. As output current increases/load resistance decreases, a larger voltage will be dropped across the internal transformer resistance. This same phenomenon is present in AC and DC systems (such as batteries).
The secondary (output) voltage is determined by the primary voltage and the turns ratio of the transformer. The secondary current is determined by the secondary voltage and the load resistance.
raised voltage output
No. A potentiometer is a variable resistor that allows you to set a voltage ratio or to adjust a resistance in a circuit. A voltage regulator, on the other hand, is a device that responds to changes in load, making automatic correction of output voltage. If you increase the load on a potentiometer, the output voltage will change, but not so (within limits) for a voltage regulator. However, you can use a potentiometer in a voltage regulator to make the output adjustable.
It does :)
Use thevenin model for the output of the power supply. That means there is a voltage source Vs, output resistance Rs and the series load RL which is a short with a resistance value equal to zero ohms. So, voltage across it is zero. The full voltage drops across the resistance Rs according to KVL.
"Transistor" name itself revels it transfers resistance from its input to its output (Transfer of resistance). Input resistance varies when input voltage varies, similarly output resistance varies and this leads to voltage variation at the output. Thus input to output voltage variation is called amplification. this is how transistor can be used as an amplifier. If input voltage is minimum output voltage becomes maximum i.e. its output resistance becomes maximum in common emitter configuration. Thus if no voltage is applied at the input its collector resistance becomes infinite or as if open circuit. Similarly if input current is increased output current increases and out put can behave as short circuit. This is how output current can be switched off or on using no input current or with minute input current. Unlike a digital device, the transistor is an analogue device which can be switch on/off to maximum or any gradient in between. Providing a small AC voltage to the base creates an amplified analogue of this signal across the emitter and collector.
No, the output will remain constant. If you double all the values, the divider ratio will not change, and it is the ratio that determines the output voltage. The current flow through the divider itself will change, it will be half the original value. This could affect the accuracy of the divider. For the same accuracy, the minimum load resistance would be double the original value.