If 185 J went in and 153 J came out (with 32 J lost to heat), the efficiency would be 153/185, 0.827 or 82.7%.
Efficiency = Wout/Win * 100%Efficiency = 170 J/250 J * 100% = 68%
it is the amount of work that can be done. a machine can use 300,000 J of energy but it only uses 263,000 J. that is percent efficiency.
The efficiency is (output energy)/(input energy) = 340/400 = 85%
30
yes
Efficiency = Wout/Win * 100%Efficiency = 170 J/250 J * 100% = 68%
Output 36.31 m3 at 8.32 sec but machine is 153 m3 at 60 minproduce air what is efficiency?
his weight is 153.
it is the amount of work that can be done. a machine can use 300,000 J of energy but it only uses 263,000 J. that is percent efficiency.
185°F is equal to 85°C. To convert F° to C°, subtract 32 and multiply by .5556 (or 5/9).185 - 32 = 153 x .5556 = 85.0068 or 85° rounded down.
Efficiency=Useful energy output divided by the energy input. i.e. 100 J is the energy input and you get 5 J light energy from a lamp, the waste energy would be 5 J.
J. Piesse has written: 'Efficiency issues in transitional economies' -- subject(s): Industrial efficiency, Economic conditions, Production (Economic theory)
Efficiency = (output/input) x 100 = (80/320) x 100 = 25%
J. Butson has written: 'Energy efficiency technology for swimming pools'
The efficiency is (output energy)/(input energy) = 340/400 = 85%
It depends on the fuel efficiency of your vehicle as well as your driving style.
J. A. Harrop has written: 'The effect of fibre configuration on the efficiency of aerosol filtration'