long hand: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p2
Short hand: [Kr] 5s2 4d10 5p6
*Remember the numbers after the letter is written as an exponent*
[Xe] 6s24f145d4
Beryllium electron configuration is [He]2s2.
abbreviated electron configuration = e.c.
tin tends to lose electrons
(Xe)6s24f145d4
Tin. {http://en.wikipedia.org/wiki/Tin}.
The electron configuration of tin(II) cation is [Kr]5s2.4d10.
The electronic configuration of tin is: [Kr]D10.5s2.5p2.The electronic configuration of chromium(2+) is correct.
5s25p2 The 2's are exponents on the s and the p
Tin has 4 valence electrons. Because of this, Tin needs to lose the 4 electrons to make it stable. Thus the answer is SN4+
Iodine is the element with that configuration.
It could be either Sn2+ ion (stannous ion) or Sn4+ ion (stannic ion)
[Xe] 6s24f145d4
The electron configuration is the number of electrons in each energy level of an element. The electron configuration of Li is, 1s2 2s1. The electron configuration of F is, 1s2 2s2 2p5.
The electron configuration for oxygen is [He]2s2.2p4.The electron configuration for sulfur is [Ne]3s2.3p4.
The electronic configuration of einsteinium is: [Rn]5f11.7s2.
The electron configuration of curium is [Rn]5f7.6d1.7s2.