i at first wrote out the enthalpies of combustion for hydrogen ethene and ethane and then manipulated the equations , ultimately my answer ended up being -137 but when i tried to find out the enthalpy on Google it just came up this quiestion did you find out what the answer was!?
Enthalpy change is delta H = -14.10*10-5J/mol at 298 K and p=po (and H2Oliquid)
-166
According to Einstein's equation, E = mc2, any time there is energy released by a chemical reaction there must be a change in mass. The factor, c2,is such a hugh factor that the mass change is so small that it is not measurable by our balances.
GeV (giga-electron-volt) is simply a unit of energy, often used for subatomic particles. Because in the subatomic world the mass-energy equivalence is much more obvious than in the large-scale world, it is often also used as a unit of mass. MeV/c2 or GeV/c2 is technically more correct, but the c2 factor is often implied, i.e., omitted.
Generally accepted that the total mass before = total mass afterwards. To be a bit pedantic, if heat energy is produced or absorbed then the total mass must change by E/c2 (which is tiny) because of Einstein's famous relation between mass and energy. This would generally appear as a temperature change.
Through Photosynthesis. The plant absorbs the solar energy, the carbon (C2), and water (H2O) and it creates the glucose (C6H12O6 + 6 O2).
I rather believe the question ask the kinetic energy equals to rest mass energy of electron. If it would state the figure of rest mass of 9.111 x 10-31 kg = kinetic energy of 9.111 x 10-31 J the unit should be given more clearly. It is given rest mass of 9.111 x 10-31 kg and rest mass energy is calculated by E = mC2 The kinetic energy is Ek = mC2/(1-v2/C2)0.5 - mC2 and for Ek = mC2 It is solving for mC2 = mC2/(1-v2/C2)0.5 - mC2 --> 2mC2 = mC2/(1-v2/C2)0.5 2 = 1/(1-v2/C2)0.5 Solve for v should not be too hard for you. Now, the momentum You must notice that when v is close to speed of light (C), you can't simply use momentum = mv but rather P = mv/(1-v2/c2)0.5 Use v obtained from above to solve for momentum.
No. You might say it is "pure energy", but any energy has an associated mass, according to the formula e = mc2. Thus, the associated mass can be calculated as m = e/c2. (Therefore, it will also have momentum.)
A better equation would be dE=dm*c2 showing that a change in mass is equivalent to a change in energy
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The conservation of energy tells us that energy before the collision equals energy the comes out of the system after the collision. In the case of a stationary target nuclei and a neutron beam we have as our initial energy Rest mass (E - mc2) of the nuclei and the particle in the beam. Kinetic energy of the nuclei and the neutron projectile. So the initial energy looks like KEn + mn*c2 + KEnuc + mnuc*c2 We note that the initial KE of the stationary nucleus is zero and omit this term. KEn + mn*c2 + mnuc*c2 Assuming neutron absorption (i.e. only 1 particle) all of the energies after the collision are described by KEnuc_f + mnic_f*c2 Use the principle of conservation of energy to set the two equal to one another. KEn + mn*c2 + mnuc*c2 = KEnuc_f + mnic_f*c2 Now solve for the final KE of the combined nuclei, KEnuc_f KEnuc_f = (KEn + mn*c2 + mnuc*c2) - (mnic_f*c2) This is the recoil energy.
That would be combustion with the products being carbon dioxide and water (assuming complete combustion) and a release of energy.
It means that there is a certain equivalence between matter and energy. For example, every amount of energy has an associated mass. c2 (the square of the speed of light) simply is the conversion factor. In SI units, that means that 1 joule of energy has an associated mass of 1 / (9 x 1018) kilograms.
According to Einstein's equation, E = mc2, any time there is energy released by a chemical reaction there must be a change in mass. The factor, c2,is such a hugh factor that the mass change is so small that it is not measurable by our balances.
The c2, which is the speed of light squared, is the conversion factor when making the conversion between mass and energy or vice versa. We see that E = mc2 and we can move the c2 to the other side. It will then be E/c2 = m. Whatever you're going to do, that is, whatever conversion you make, the c2 is the conversion factor in the operation.
Basically, you get less matter after both processes. The energy achieved can be calculated by E = m*c2. E = Energy. m = the mass "disappeared". c2 = speed of light squared.
as for as iam concerned i think albert sir multiply m with C2 becoz when a mass moves with this velocity then it become in the form of energy.
80,000 miles or 10 years. But if your in any doubt change it now.
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