The energy of a 589 nm photon is 1.25uev/.589um=2.1222 ev (electron volts).
The energy of a photon can be calculated using the equation E = hc/λ, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J*s), c is the speed of light (3.0 x 10^8 m/s), and λ is the wavelength of the photon. Plugging in the values, the energy of a photon emitted with a wavelength of 654 nm (or 6.54 x 10^-7 m) is approximately 3.02 x 10^-19 J.
If you know the frequency of a light wave, you can tell the wavelength, thecolor it'll appear to your eye, and the energy in each photon of the light.The energy of the wave ~APEX
A photon, or particle of light, is released.
-- I have to assume that the '520' figure is also a wavelength in nm.-- The energy of a photon is proportional to its frequency. That also meansthat the energy is inversely proportional to its wavelength. So the photonwith the greater wavelength has less energy.-- 720/520 = 1.385The shorter-wave photon has 38.5% more energy than the longer-wave one.-- 520/720 = 0.722The longer wave photon has 72.2% as much energy as the shorter-wave one has.
The particle-like features of EM radiation at frequencies of radio waves are almost non-existent. It is far more useful to view such radiation as a vibrating EM-field instead of a photon of almost no energy. When doing so, you can see how a EM wave would result from electrons vibrating back and forth at at set frequency. By setting up an electronic oscillator that has a resonance at a radio wave frequency, you will get electrons vibrating at that frequency; and, from that, an EM wave of that frequency. > are photons emitted only by electrons jumping from higher to lower energy levels? No, there are many other ways to accomplish this.
assuming the wave is electromagnetic... the energy of a single photon of that frequency is given by the formula E=hf where E= energy of the photon h=the Planck constant f= the frequency of the photon From this the energy of the photon is the Planck constant (6.63 x10-34) multiplied by the frequency 3.6x1016 Hz. E= 23.9x10-18 Joules. The wavelength of any wave is determined by the equation wave speed = frequency x wavelength. thus, the wavelength is the wave speed divided by the frequency. since all electromagnetic waves travel at the speed of light then... wavelength = 3x108 / 3.6x1016 wavelength = 0.83x10-8 = 8.3x10-9 metres. The electromagnetic radiation corresponding to this energy and wavelength is ultraviolet radiation and may be of interest to nuclear medicine.
If you know the frequency of a light wave, you can tell the wavelength, thecolor it'll appear to your eye, and the energy in each photon of the light.The energy of the wave ~APEX
No, sound wave is translating wave of the matter. The solar energy is the wave carried by photon which is an energy (non-matter). There is no way a sound wave would be carried in the stream of photon.
If we condier the wave in the form of photons, then as wavelength increases then energy content of each photon decreases.
Photon
Either as: A particle, the photon, A packet of energy, the quantum of electromagnetism(still known as the photon), and A wave of a specific frequency, a wave of radiation that has a certain energy
Energy of a photon of this wave would be (planck's constant) ( frequency) E = hf = 5.46 * 10-22 J So to find the energy of the whole wave, multiply the energy of a photon to the no. of photons in a wave.
I presume you asking, "How can an atom of size about 1 angstrom absorb a photon whose wavelength is 5000 angstroms? Wouldn't the photon be too large for that atom?" The paradox is resolved in this way: the instant you start to discuss electro-magnetic radiation as a photon instead of a transverse electro-magnetic wave, then you negate the wave-length aspect of the light. Instead, you view light as a collection of photons -- particles whose "size" (if that word has meaning) is point-like -- with a specific energy instead of specific wavelength. A photon is NOT a snake-like wave, vibrating like a rubber band, with a length at least that of its wave-length, as it moves through a medium. A photon is a point particle with a specific energy. You can describe light as a EM wave with a wave-length OR as a collection of point particles. You can NOT do both at the same time. Light exhibits the characteristics of one OR the other, but NEVER both.
radiation
The shorter the wave length the more energy. The further the electron falls, the more energy that will be emitted and the shorter the wavelength.
The amount of energy in a photon of light is proportional to the frequency of the corresponding light wave.... frequency of the electromagnetic radiation of which the photon is a particle.
A photon, or particle of light, is released.
It really depends on the type of wave. In the case of electromagnetic waves, a higher frequency results in more energy per photon. Therefore, a longer wavelength results in less energy per photon.