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The energy of a photon is inversely propotional to its wavelength. The wavelength of a blue photon is less than that of a red photon. That makes the blue photon more energetic. Or how about this? The energy of a photon is directly proportional to its frequency. The frequency of a blue photon is greater than that of a red photon. That makes the blue photon more energetic. The wavelength of a photon is inversely proportional to its frequency. The the longer the wavelength, the lower the frequency. The shorter the wavelength, the higher the frequency.
Light of is made up of a finite number of photons, or light quanta. The energy of each photon is proportional to the frequency of the light, and hence inversely proportional to the wavelength of the light. Red light has a longer wavelength than blue light, so the quantum of red light has less energy than the quantum of blue light.
The violet light has more energy than the red light. Red light is lower on the electromagnetic spectrum, meaning it has a lower frequency (or longer wavelength). You'll recall the colors of the rainbow as red, orange, yellow, etc., and these are the colors going up the frequency spectrum. Photons higher on the spectrum are higher in frequency and energy.
A rough definition of intensity (how intense) a light is might be how bright (the brightness) the light is. Intensity speaks to the luminance or luminosity of the light source. Under that definition, either red or blue light could be more intense. But if the information regarding the energy of light according to its color (or its wavelength or frequency), we would find that a photon of blue light has more energy than a photon of red light. Blue light has a shorter wavelength or higher frequency, and electromagnetic energy with higher frequency or shorter wavelength has more energy than light of the same intensity but of lower frequency or longer wavelength.
No, it could not. A blue photon carries more energy than a red photon, since the blue photon's frequency is higher. That means one red photon wouldn't deliver enough energy to the atom to give it the energy to emit a blue photon.
The energy of a photon is inversely propotional to its wavelength. The wavelength of a blue photon is less than that of a red photon. That makes the blue photon more energetic. Or how about this? The energy of a photon is directly proportional to its frequency. The frequency of a blue photon is greater than that of a red photon. That makes the blue photon more energetic. The wavelength of a photon is inversely proportional to its frequency. The the longer the wavelength, the lower the frequency. The shorter the wavelength, the higher the frequency.
Wavelength Frequency and Photon Energy
Light of is made up of a finite number of photons, or light quanta. The energy of each photon is proportional to the frequency of the light, and hence inversely proportional to the wavelength of the light. Red light has a longer wavelength than blue light, so the quantum of red light has less energy than the quantum of blue light.
The violet light has more energy than the red light. Red light is lower on the electromagnetic spectrum, meaning it has a lower frequency (or longer wavelength). You'll recall the colors of the rainbow as red, orange, yellow, etc., and these are the colors going up the frequency spectrum. Photons higher on the spectrum are higher in frequency and energy.
If the color (frequency, wavelength) of each is the same, then each photon carries the same amount of energy. Three of them carry three times the energy that one of them carries.
The blue light has longer wavelength, lower frequency, andless energy per photon than the ultraviolet light has.The blue light is also visible to the human eyes, whereas theultraviolet light is not.
A rough definition of intensity (how intense) a light is might be how bright (the brightness) the light is. Intensity speaks to the luminance or luminosity of the light source. Under that definition, either red or blue light could be more intense. But if the information regarding the energy of light according to its color (or its wavelength or frequency), we would find that a photon of blue light has more energy than a photon of red light. Blue light has a shorter wavelength or higher frequency, and electromagnetic energy with higher frequency or shorter wavelength has more energy than light of the same intensity but of lower frequency or longer wavelength.
All particles which represents a quantum of light and other electromagnetic radiation is called photon. The photons with the highest energies are gamma or X-rays, UV light, Blue light, and radio waves.
No, it could not. A blue photon carries more energy than a red photon, since the blue photon's frequency is higher. That means one red photon wouldn't deliver enough energy to the atom to give it the energy to emit a blue photon.
X-ray. The energy of a light photon is inversely proportional to its wavelength. (so as the wavelength shortens, the energy goes up.) X-rays have the shortest wavelengths of the types of light you mentioned. In order of energy highest to lowest, the lights you mentioned would be: x-ray, ultraviolet, blue, microwave.
High-energy photons correspond to short-wavelength light while low-energy photons correspond to long-wavelength light. In short, the answer is red. For short-wavelengths (high energy photons) it would appear blue.
Red does as it absorbs photons at blue end of the spectrum( the higher energy) and reflects light at the red end of the spectrum (a lower energy). While the blue light absorbs energy at the red end of the spectrum and reflects blue light