The energy is E=hf= 2/3E-33 x 5E14= 1/3 E-18 Joules.
When the frequency of a wave increases, the energy of the wave also increases. This is because energy is directly proportional to frequency, as given by the equation E=hf, where E is energy, h is Planck's constant, and f is frequency. Higher frequency waves have more energy per photon.
Yes. The energy is given by plank's constant times the frequencie of the photon (remember that light is both particle and wave). So since blue light has higher frequency than green light, it is more energetic.
The frequency of a photon can be calculated using the equation E=hf, where E is the energy of the photon, h is Planck's constant (6.63 x 10^-34 Js), and f is the frequency. Rearranging the formula gives f=E/h. Plugging in the values, f = (3.26 x 10^-19 J)/(6.63 x 10^-34 Js) = 4.92 x 10^14 Hz.
Those numbers are very inaccurate for visible light. But it doesn't matter. The rule is that the energy carried by a photon of any electromagnetic radiation is proportional to its frequency. The higher the frequency, the more energy it carries.
A quantum of light energy is called a photon. It is the smallest unit of light energy that behaves both like a particle and a wave. Photons carry electromagnetic radiation and have properties like energy, momentum, and frequency.
E = h f (relation of energy with frequency) E = h c / λ (relation of energy with wavelength) h = Planck's constant ≈ 6.026 × 10⁻³⁴ J.s c = speed of light = 299,792,458 m/s in vacuum ≈ 3.0 × 10⁸ m/s
To calculate the energy of an x-ray photon, you can use the formula E = hf, where E is the energy, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency of the photon. First, convert the frequency from Hz to s^-1. Then, plug in the values to find the energy in joules, which can be converted to keV by dividing by 1.6 x 10^-16.
4.9695 nm
107.1 MHz has higher energy photons. The photon energy increases directly proportional to frequency. However if the station operating on 90.5 MHz transmitter's power is 1.184 times or higher than that of the station operating on 107.1 MHz transmitter's power, then the 90.5 MHz signal will have higher energy because the additional photons makeup the difference. The total energy in electromagnetic radiation is the product of the energy per photon and the number of photons (i.e. amplitude of the wave) in the radiation.
the atom is obvorbed with a structre of strikes which can power a energy photon by 31 x10 but can obloute to -19. the sequal atom is a number of strikes added to a molecue. answer: high mark.
its because the gallium emites heat and a negligable photon energy
Those are the ones with the highest frequency/shortest wavelength/most energy per photon. Most . . . gamma rays Next most . . . X-rays . . . Least . . . low-frequency radio waves