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No, it could not. A blue photon carries more energy than a red photon, since the blue photon's frequency is higher. That means one red photon wouldn't deliver enough energy to the atom to give it the energy to emit a blue photon.
energy of one packet of light
The energy in one photon of any electromagnetic radiation is directly proportionalto its frequency, so that would be inversely proportional to its wavelength.Note: There is no energy in the protons of light, since light has no protons.
when one of its electrons is boosted to a higher-energy excited state upon being struck by a photon of light.
When light (a photon) collides with an atom, the energy contained by it is absorbed and it bumps one of the electrons orbiting it up to a higher energy level. ( there are several energy levels, think of it as stories of a building) Later when the electron falls down 1 or more energy levels, The energy is released as another photon. If the electron drops down to the original energy level, the same intensity photon is released as was absorbed. If it drops down in 2 or more steps, several photons will be released of varying intensity, depending on the amount of levels dropped.
No, it could not. A blue photon carries more energy than a red photon, since the blue photon's frequency is higher. That means one red photon wouldn't deliver enough energy to the atom to give it the energy to emit a blue photon.
energy of one packet of light
If the color (frequency, wavelength) of each is the same, then each photon carries the same amount of energy. Three of them carry three times the energy that one of them carries.
If the photon is having very less frequency (say v=1Hz) ,then the Energy of such photon will be the smallest one. It can be inferred that the smallest unit of light energy will correspond to the smallest frequency of such quanta. But from the uncertainty principle it limits the energy of a quanta.
it looses energy , it gives off light in the form of a single photon.
A Photon does not have any mass. It is merely a packet of energy. To calculate the energy of a photon, the formula is E = hνwhere h = Planck's constant = 6.63 x 10-34and ν = frequency of the light source (in Hz)
The line emission spectrum of an atom is caused by the energies released when electrons fall from high energy level. It goes down to a low energy level and the extra energy it had from higher level is released as light.
This is a tricky question because there is more than one form of energy in light. There is the energy that each particle of light (the photon) has and there is group energy which is the sum total of all the photon energy as they travel as a group (like in a laser beam). But the good news is that the answer is FALSE for both the photon and group energies. Photon energy depends on the photon fundamental frequency. And the higher the energy the bluer the color, which can run from red to violet. Those photons in the violet color have higher energy than photons in the red color frequency. And group energy is just the sum of all the photon energies in a group, like a light beam from your flashlight (aka, torch). So for a given mix of photons, the more photons in the group the higher is the group energy level. What we call light intensity (e.g., bright or dim) depends on the group energy with high energy equating to high intensity.
The energy in one photon of any electromagnetic radiation is directly proportionalto its frequency, so that would be inversely proportional to its wavelength.Note: There is no energy in the protons of light, since light has no protons.
Green light. If you use the abbreviation ROY G. Biv ( red, orange yellow, green, blue, indigo, violet), you will always know that the red light has the longest wavelength and violet has the smallest wavelength. Wavelength and frequency are inversely proportional to one another. So if the wavelength is large, frequency is small, and when wavelength is small, frequency is large. Green light has a smaller wavelength than yellow. Likewise it has a higher frequency than yellow does. Therefore, green light has a higher frequency than yellow light.
The energy in one photon of any electromagnetic radiation is directly proportionalto its frequency, so that would be inversely proportional to its wavelength.Note: There is no energy in the protons of light, since light has no protons.
when one of its electrons is boosted to a higher-energy excited state upon being struck by a photon of light.