it would be unditermand because noone actually knows what infinity is because numbers go on forever :)
No, xenon does not have electrons in the n equals 5 energy level in its ground state. In its ground state, xenon's electron configuration fills up to the n equals 4 energy level before moving on to higher energy levels for excited states or ionized forms.
n=1 is the the lowest level there is.
Energy
5
when n = 0 it equals -25 when n = 1 it equals -36 when n = 2 it equals -39 etc
5-2=3n=3
n =33
Oh, dude, if 5 plus n equals 23, then n must be 18, right? So, if you wanna find out what n minus 5 equals, just subtract 5 from 18 and you get 13. Easy peasy lemon squeezy.
Absorb appx 12.1eV (electron Volts) of energy. Energy of 1st level is -13.6eVEnergy of 3rd level is -1.5eV Hence, energy required = 13.6 - 1.5 = 12.1 eV
Shorter wavelength = more energy. The farther the electron falls, the more energy that will be emitted.
As n increases, the energy increases. Therefore, electron in the shell of n=100 will have highest energy. But the fact is that there isn't any shell with n=100. Also, n can have values starting from 1 and thus n=0 is not possible as well.
If: n/5 = 27 Then: n = 135.