Energy
Se2- 1s22s22p63s23p64s23d104p6
Helium (He) is the element that has a negative electron affinity. This means that it is less likely to gain an electron compared to other elements listed (Kr, O, Ca, and Mg) which have positive electron affinities.
Yes, barium has a lower ionization energy than calcium. This is because barium is located further down in Group 2 of the periodic table, meaning it has more electron shells and greater electron shielding. As a result, it requires less energy to remove the outermost electron compared to calcium, which is higher up in the group.
As n increases, the energy increases. Therefore, electron in the shell of n=100 will have highest energy. But the fact is that there isn't any shell with n=100. Also, n can have values starting from 1 and thus n=0 is not possible as well.
yes! It is because Neon has the largest atomic mass so the force of attraction between electrons and protons in the positively charged nucleus is the highest compared to all the other electrons in period 2.
Shorter wavelength = more energy. The farther the electron falls, the more energy that will be emitted.
S orbital
just gotta you know do it
The phrase "complain more" is likely a playful way to express that the sum of negative 4 and 3, which equals -1, feels more negative than the sum of negative 3 and 5, which equals 2. In essence, -1 can be seen as a less desirable outcome compared to 2, which is positive. Therefore, the "complaint" stems from the greater negativity of -1 compared to the positivity of 2.
Se2- 1s22s22p63s23p64s23d104p6
Oxygen is on period 2 whereas sulfur is on period 3. Therefore, sulfur has more electron shells than oxygen.
Helium would be least reactive because its last electron shell is full with 2 electrons, giving it a stable electron configuration. Neon also has a full outer electron shell but belongs to the noble gases group. Helium is a noble gas, hence more stable and less reactive compared to lithium and bromine.
No, because is n=1, the electron is in the first energy level, therefore cannot have a l=2, because l= n-1. Or more simply put l=2 is a d-orbital, and there are no d-orbitals in the first energy level. ml=0 is correct because ml= +-l through 0.
Sr (strontium) is bigger than Mg (magnesium) because as you move down a group (in this case, group 2 of the periodic table), the atomic size generally increases due to the addition of more electron shells. Sr, being lower in the group, has more electron shells compared to Mg.
The energy of an electron in the n equals 4 excited state can be calculated using the formula E = -13.6eV/n^2. Plugging n = 4 into the formula, the energy of the electron in the n equals 4 excited state would be -2.125 eV.
Helium (He) is the element that has a negative electron affinity. This means that it is less likely to gain an electron compared to other elements listed (Kr, O, Ca, and Mg) which have positive electron affinities.
Yes, barium has a lower ionization energy than calcium. This is because barium is located further down in Group 2 of the periodic table, meaning it has more electron shells and greater electron shielding. As a result, it requires less energy to remove the outermost electron compared to calcium, which is higher up in the group.