The enthalpy of neutralization of a strong acid against a strong base is always constant (13.7 kcal or 57 kJ mole-1). It is because in dilute solutions all strong acids and bases ionize completely and thus the heat of neutralization in such cases is actually the heat of formation of water from H+ and OH- ions, i.e.,
H+ + OH- ---> H2O; ΔH = -13.7 kcal
There is no connection between enthalpy of neutralisation and whether the acid is weak or strong. The enthalpy of the reaction depends on ALL reactions and changes that happen, not just the one involving the hydrogen ion.
Because the value changes at a constant degree
Actually your question should sound "Why is the enthalpy change of neutralization of STRONG ACID and STRONG BASE equal to -57.2kJmol-1?". This is because when STRONG ACID and STRONG BASE react and neutralization process occur, a complete ionization will occur. Therefore, they will have almost the same value of enthalpies and can be assummed to be -57.2kJmol-1. As per mentioned that if your question sounds "Why is the enthalpy change of neutralization of STRONG ACID and STRONG BASE equal to -57.2kJmol-1?", then my explaination above will be helpful. However, if it doesn't sound like mine and you insisted with your question titled "Why is the enthalpy change of neutralization equal to -57.2kJmol-1", then my answer is that they didn't equal to -57.2kJmol-1 and it varies from the list of reactants. 1. STRONG acid + STRONG base = -57.2 2. WEAK acid + WEAK base = less than 57.3kJmol-1 3. WEAK acid + STRONG base = more negative than -57.3kJmol-1 Wish that it is useful as your reference. Prompt me if I am wrong.
use the formula for enthalpy change for the reaction of an acid and base to produce 1mol of water. dH=mc(dT)/n where H = enthalpy m = mass of system c = specific heat capacity of system T = temperature of system n = number of moles reacted
Because it doesnt have water
Yes, it is. Sodium hydroxide and hydrochloric acid are both strong base and strong acid. It means that they dissociate fully in water. In neutralisation reaction the products of the reaction are: water, and salt of the two compounds. NaOH + HCl -> NaCl + H2O No H3O+ and OH- ions are formed, therefore solution after the reaction is neutral. There is but one condition, the reactants must be mixed stoichiometrically.
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Actually your question should sound "Why is the enthalpy change of neutralization of STRONG ACID and STRONG BASE equal to -57.2kJmol-1?". This is because when STRONG ACID and STRONG BASE react and neutralization process occur, a complete ionization will occur. Therefore, they will have almost the same value of enthalpies and can be assummed to be -57.2kJmol-1. As per mentioned that if your question sounds "Why is the enthalpy change of neutralization of STRONG ACID and STRONG BASE equal to -57.2kJmol-1?", then my explaination above will be helpful. However, if it doesn't sound like mine and you insisted with your question titled "Why is the enthalpy change of neutralization equal to -57.2kJmol-1", then my answer is that they didn't equal to -57.2kJmol-1 and it varies from the list of reactants. 1. STRONG acid + STRONG base = -57.2 2. WEAK acid + WEAK base = less than 57.3kJmol-1 3. WEAK acid + STRONG base = more negative than -57.3kJmol-1 Wish that it is useful as your reference. Prompt me if I am wrong.
you create a neutral solution -------------------------------------------------------------------------------------------- Well it depends actually it doesn't always create a neutral solution. Here's the order: Strong Alkali + Strong Acid = Neutralisation (water + salt) Strong Alkali + Weak Acid = Weak Alkali Weak Alkali + Weak Acid = Neutralisation ( water + salt) Weak Alkali + Strong Acid = Weak Acid Strong Alkali + Strong Acid = Neutralisation (water + salt) Hope it helps! :)
pH7,Which It Water.
It depends you can sometimes get an alkaline salt.if you use a strong acid and a weak base during neutralisation you will get an acidic salt (eg. Ammonia chloride. Made from hydrochloric acid and ammonia) However, if you use a weak acid and a strong base during neutralisation you will get an alkaline salt (eg. Sodium ethanoate. Made from sodium hydroxide and ethanoic acid)
use the formula for enthalpy change for the reaction of an acid and base to produce 1mol of water. dH=mc(dT)/n where H = enthalpy m = mass of system c = specific heat capacity of system T = temperature of system n = number of moles reacted
Enthalpy of solution of oxalic, succinic, adipic, maleic, malic, tartaric, and citric acids, oxalic acid dihydrate, and citric acid monohydrate in water at 298.15 K
no if the acid is strong and the base is weak then the salt will be slightly acidic. sources: chemistry teacher :)
Stomach acid is hydrocloric acid. This has a pH scale of 1. This is tackled by a strong alkali to make the pH 7. aka neutral
Yes. An acid-base neutralisation is exothermic, so energy will be released and part of this energy will heat the mixture.
neutralisation.... i..think.................
acid + base --> water + salt