2 H2C2 (g) + 5 O2 (g) --> 4 CO2 (g) + 2 H2O (g)
http://chemed.chem.purdue.edu/demos/demosheets/24.9.html
Actually the correct way to write this would be
2 C2H2(g) + 5 O2 (g) --> 4 CO2 (g) + 2 H2O (g)
Because C2H2 is acetelyne properly written
You ask this as if all forms of incomplete combustion would be described by the same equation; different fuels have different equations for either complete or incomplete combustion. I will add that it would be characteristic of many forms of incomplete combustion that one of the combustion products is carbon monoxide.
CH4 + 3O2----> Co2 + 2H2o+ Co
The general word equation for complete combustion is:
hydrocarbon + oxygen --> carbon dioxide + water
It depends on WHAT you want to burn with oxygen:
For alkanes like CH4 (methane, natural gas) or C8H18 (octane, petrol) the general balanced equation of complete combustion is as follows
CnH2n+2 + (3n+1)/2 O2 ==> n CO2 + (2n+2)/2 H2O for each uneven(*) natural value of n
(*) if n is even, then all coefficients should be doubled to prevent 'halve' values at the end.
Example butane:
will become:
(because 6.5 O2 is not allowed)
3C2H2 + 5O2 --> C + 3CO + 2CO2 + 3H2O
3C2H2 + 4O2 --> 2C + 3CO + CO2 + 3H2O
4(c2h6) +3(o2) --> 3(co) + 5(c) + 3(h2o)
The chemical reaction is:
3 CH4 + 5 O2 ----> 2 CO + CO2 + 6 H2O
the equation is C2H6 + 2O2 ------> CO +C +3H2O
2c2h2 + 5o2 ----> 4co2 + 2h20
Incomplete combustion of decane is ...2 C10H22 + 21 O2 ==> 20CO + 22H2O
exc. H2 + nO2 ---> 2nH2O + exc. H2.
Undecane - C11H243-methyl-4-propylheptane
For example the preparation of caramel can be considered an incomplete combustion.
-51.88 kJ/g
The chemical reaction is:2 C2H6 + 5 O2 = 4 CO + 6 H2O
Incomplete combustion of Methane is....2CH4 + 2O2 --> CO + C + 4H2O
Incomplete combustion of decane is ...2 C10H22 + 21 O2 ==> 20CO + 22H2O
Incomplete combustion of Methane is....2CH4 + 2O2 --> CO + C + 4H2O
CO
Burning of methane is:CH4 + 2 O2---------- → CO2 + 2 H2OCarbon monoxide is released after an incomplete combustion.
exc. H2 + nO2 ---> 2nH2O + exc. H2.
C12h23+11.75o2=12co+11.5h20
a chemistry is a scientist Technology And Imbued To the School And Bright
Not exactly. Natural gas is mostly methane with small amounts of ethane and thiols. Incomplete combustion of this will yield some carbon monoxide.
Undecane - C11H243-methyl-4-propylheptane
The Main danger of incomplete combustion is the production of carbon monoxide.