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What is the equation to calculate power when circuit current and resistance are known what is the equation?
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What is the amperage in an electric circuit when the voltage 120 volts and the resistance is 40 ohms?
Ohm's Law states Voltage = Current x Resistance. You rewrite the equation as Current = Volts / Resistance to solve for current.
What is common to both thevenin and norton theorem?
To solve any D.C. circuit by using Thevenin Theorem,First of all load resistance RL is disconnected from the circuit and open circuit voltage across the circuit is calculated (known as Thevenin equivalent voltage)Secondly, the battery is removed by leaving behind its internal resistance. Now we calculate equivqlent resistance of the circuit ( called Thevenin equivalent resistance).Now we connect Thevenin Voltage in series with Equivalent resistance of the circuit and now connect load resistance across this circuit to calculate current flowing through the load resistance.Whereas in the case of using Norton theorem, we again remove the load resistance if any, and then short circuit these open terminals and calculate short circuit current Isc.Second step is same as in Thevenin theorem i.e. remove all sources of emf by replacing their internal resistances and calculate equivqalent resistance of the circuit.Lastly, join short circuit current source in parallel with equivalent resistance of the circuit. Now, we can calculate votage across the resistance which was connected in parallel with Isc.So, by knowing the open circuit voltage, we can calculate current flowing the resistance and on the other hand , by knowing the short curcuit current , we can calculate voltage across the resistance.
When current remains constant and resistance increases the voltage in the circuit will?
The physical equation governing voltage is V = IR, where V is voltage, I is current, and R is resistance. If V remains constant while R is increased, I or current must decrease. Increasing the resistance in a circuit is simply introducing a material that further resists or impedes the electron flow (current), thus current decreases.
Why doesn't current decrease in series resistance circuit though resistance opposes current?
If you add another resistor or just increase the resistance the current will decrease. I think the statement you are talking about means that whatever the current is in the series circuit it will be the same everywhere in that circuit, on both sides of the resistance. The resistance lowers the current in the entire circuit, not just after the resistance.
Will voltage or current be higher in a circuit during short circuit?
Since a short circuit is, essentially, a zero impedance connection between nodes, the current in a short circuit is limited only by the ability of the source. In the case of an ideal voltage source connected to an ideal short circuit, you would have infinite amperes.
What is an equation for power?
Power = (energy used)/(time to use it)Power dissipated by an electrical circuit =(voltage across the circuit) x (current through the circuit)or(resistance of the circuit) x (square of the current through the circuit)or(square of the voltage across the circuit)/(resistance of the circuit)
What is the amperage in an electric circuit when the voltage 120 volts and the resistance is 40 ohms?
Ohm's Law states Voltage = Current x Resistance. You rewrite the equation as Current = Volts / Resistance to solve for current.
How do you calculate the voltage in a circuit with a resistance of 20hms and a currents of 6?
Use Ohm's Law. In this case, multiply the resistance by the current.
What is the relationship among voltage circuit and resistance in a circuit?
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
How do you find resistance when you have current and resistance total?
If you are looking for the resistance of each resistor in either a series circuit or a parallel circuit you must measure the current I and the voltage V for each resistor. Then calculate its resistance using Ohms Law R = V / I where I = current (Amps), V = voltage (Volts) and R= resistance (Ohms).
What is common to both thevenin and norton theorem?
To solve any D.C. circuit by using Thevenin Theorem,First of all load resistance RL is disconnected from the circuit and open circuit voltage across the circuit is calculated (known as Thevenin equivalent voltage)Secondly, the battery is removed by leaving behind its internal resistance. Now we calculate equivqlent resistance of the circuit ( called Thevenin equivalent resistance).Now we connect Thevenin Voltage in series with Equivalent resistance of the circuit and now connect load resistance across this circuit to calculate current flowing through the load resistance.Whereas in the case of using Norton theorem, we again remove the load resistance if any, and then short circuit these open terminals and calculate short circuit current Isc.Second step is same as in Thevenin theorem i.e. remove all sources of emf by replacing their internal resistances and calculate equivqalent resistance of the circuit.Lastly, join short circuit current source in parallel with equivalent resistance of the circuit. Now, we can calculate votage across the resistance which was connected in parallel with Isc.So, by knowing the open circuit voltage, we can calculate current flowing the resistance and on the other hand , by knowing the short curcuit current , we can calculate voltage across the resistance.
In series circuit is currant change with change in resistance?
V=IR where V is voltage, I is current and R is resistance. You want to know what the current will be in a series circuit based on the resistance. You need to know the voltage as well as the resistance, gives you the equation as follows I=V/R So if you have 10 volts and a 1 ohm resistor, the current will be 10 amps. If you increase the resistor to 10 ohms, your current will then be 1 amp. In a parallel circuit, the resistance is equal to the sum of the inverse. For example. If I have two resistors of 2 ohms each in parallel, the equation would be 1/2 + 1/2 = 0.5 + 0.5 = 1 In that particular instance, your current would increase.
When resistance is in a circuit what happens to the current?
When you add resistance to a circuit, current goes down. Ohm's Law: current = voltage divided by resistance.
When current remains constant and resistance increases the voltage in the circuit will?
The physical equation governing voltage is V = IR, where V is voltage, I is current, and R is resistance. If V remains constant while R is increased, I or current must decrease. Increasing the resistance in a circuit is simply introducing a material that further resists or impedes the electron flow (current), thus current decreases.
How do you calculate short circuit current?
A short circuit = 0 ohm, from this one can use ohms law to calculate the current, that is E/R voltage divided by resistance as in this instance your resistance is zero and you can't divide by zero so your current will be infinit. In other words if your power supply is large enough to supply 200 amp, your current on a short circuit will be 200 amp.
Why doesn't current decrease in series resistance circuit though resistance opposes current?
If you add another resistor or just increase the resistance the current will decrease. I think the statement you are talking about means that whatever the current is in the series circuit it will be the same everywhere in that circuit, on both sides of the resistance. The resistance lowers the current in the entire circuit, not just after the resistance.
Diode reverse breakdown14v current of 70mA and an un-stabilised supply voltage of 28v calculate resistance?
If a circuit element has a voltage of 14V and a current of 70mA, then the resistance of the circuit element is 200 ohms. This is ohm's law. The resistance or type of the power supply is meaningless.
