.01 M
CaCl2(aq) + Pb(NO3)2(aq) ===> Ca(NO3)2(aq) + PbCl2(s) so a precipitate of PbCl2 (lead chloride) will form. The fact that equal volumes of 0.2 M are mixed indicates that all of the Pb^2+ and all of the Cl^- will precipitate out of solution leaving only Ca^2+ and NO3^- left in solution.
1. A solvent and a solute are both parts of a solution.2. The solvent is mostly in majority and, it dissolves a solute in itself to make a solution.
Let x be the ounces of 15% alcohol solution. The amount of alcohol in the 15% solution is 0.15x, and the amount of alcohol in the 23% solution is 0.23(100 - x). Setting up the equation 0.15x + 0.23(100 - x) = 0.15(100) solves for x, which is approximately 38.5 ounces of the 15% alcohol solution needed.
When sugar is mixed with water, it dissolves, and an equilibrium is established between the dissolved sugar molecules and the undissolved sugar. At this point, the rate at which sugar molecules enter the solution equals the rate at which they leave the solution, resulting in a stable concentration of sugar in the water. If more sugar is added beyond its solubility limit, excess sugar will remain undissolved, indicating that equilibrium has been reached. This dynamic balance allows for the constant interaction of sugar molecules without changing the overall concentration in the solution.
A solution that contains only a low concentration of solute is often referred to as a dilute solution. This type of solution has a small amount of solute mixed with a larger amount of solvent, resulting in a lower ratio of solute to solvent. For example, a glass of water with just a few drops of food coloring is a dilute solution, where water is the solvent and the food coloring is the solute. Such solutions are commonly used in various applications, including laboratory experiments and culinary practices.
calculate final molarity of the solution if 11ml of 5m solution is made up to 20ml
The initial moles of NaCl in 1 mL of 10 mM solution is 10 µmol. The initial moles of Cl- in 4 mL of 0.05 M CaCl2 solution is 0.2 µmol. Therefore, the total moles of Cl- after mixing is 10.2 µmol. The final concentration of Cl- is 2.55 mM.
When CaCl2 and MgSO4 are mixed, they will not form a new compound. Instead, they will remain as two separate compounds in the solution.
Start with CaCl2. 250ml of 0.20M solution will give (0.2/1000)*250 moles = 0.05 moles. However, CaCl2--> Ca2+ + 2Cl- (1:2 reaction) so 0.05moles of CaCl2 will give 2* 0.05 moles cl ions =0.1moles. KCl will give (0.4/1000)* 250 moles =0.1 moles Since KCl--> K+ + Cl- (1:1 reaction) so 0.1 moles KCl will give 0.1 moles Cl ions. Add the 2 together so 0.1moles + 0.1 moles = 0.2 moles in total.
The final solution color will depend on the concentration of barium chloride and potassium chloride. However, in general, barium chloride is white and potassium chloride is colorless, so the final solution will likely appear white or colorless.
Concentration is the measure of how much of a given substrate is mixed with another substance,so it can never be negative.
A solution is evenly distributed when the solute is uniformly mixed with the solvent throughout the entire mixture. This results in a homogeneous solution where the concentration of the solute is the same in all parts of the solution. Uneven distribution would mean that the solute is not uniformly mixed, resulting in a heterogeneous solution.
CaCl2(aq) + Pb(NO3)2(aq) ===> Ca(NO3)2(aq) + PbCl2(s) so a precipitate of PbCl2 (lead chloride) will form. The fact that equal volumes of 0.2 M are mixed indicates that all of the Pb^2+ and all of the Cl^- will precipitate out of solution leaving only Ca^2+ and NO3^- left in solution.
To make a 0.1 molar solution from a 1.0 molar solution, you would dilute the original solution by a factor of 10. For example, you could mix 1 part of the 1.0 molar solution with 9 parts of solvent (like water) to achieve a final concentration of 0.1 molar.
The pH of the second solution must be neutral (pH 7), as mixing an acidic solution (pH 4) with a basic solution (pH 7) would result in a pH closer to 7. This indicates that the pH of the unknown solution is around 7 to yield a final pH of 5 when mixed with the pH 4 solution.
When an acid solution is mixed with a basic solution, there will be a neutralization reaction in which hydrogen ions from the acid will combine with hydroxide ions from the base, to form water.
When mixing a solution at pH 4 with a solution at pH 8, the final pH will be between 4 and 8. The resulting pH will depend on the ratios of the two solutions being mixed. If equal volumes are mixed, then the final pH will likely be around 6.