[1 mL*10 mM + 4 mL*(50*2 mM Cl-) ] mmolCl- in [1+4] mL total solution
This is 410 (mmol Cl-) / 5 (mL) = 82 mM Cl-
Start with CaCl2. 250ml of 0.20M solution will give (0.2/1000)*250 moles = 0.05 moles. However, CaCl2--> Ca2+ + 2Cl- (1:2 reaction) so 0.05moles of CaCl2 will give 2* 0.05 moles cl ions =0.1moles. KCl will give (0.4/1000)* 250 moles =0.1 moles Since KCl--> K+ + Cl- (1:1 reaction) so 0.1 moles KCl will give 0.1 moles Cl ions. Add the 2 together so 0.1moles + 0.1 moles = 0.2 moles in total.
Concentration is the measure of how much of a given substrate is mixed with another substance,so it can never be negative.
The reaction is: CaCO3 + 2HCl = CaCl2 + H2O + CO2
BaCl2- and KCl-solutions have no color, and also none when mixed.
A solution's concentration is a measure of solute/solvent. Solute is the thing to be mixed in (i.e. salt in salt water) and solvent is the medium, usually liquid, for the solute to be mixed in (i.e. the water in salt water). Therefore, increasing the ratio of solute to solvent would increase the concentration. This could be done by adding more solute, or removing the solvent (i.e. going back to the salt water, adding more salt, or evaporating water would increase the concentration) The converse of this is also true to decrease the concentration.
.01 M
calculate final molarity of the solution if 11ml of 5m solution is made up to 20ml
Start with CaCl2. 250ml of 0.20M solution will give (0.2/1000)*250 moles = 0.05 moles. However, CaCl2--> Ca2+ + 2Cl- (1:2 reaction) so 0.05moles of CaCl2 will give 2* 0.05 moles cl ions =0.1moles. KCl will give (0.4/1000)* 250 moles =0.1 moles Since KCl--> K+ + Cl- (1:1 reaction) so 0.1 moles KCl will give 0.1 moles Cl ions. Add the 2 together so 0.1moles + 0.1 moles = 0.2 moles in total.
That all depends on what you want the final concentration of alcohol to be.
Concentration is the measure of how much of a given substrate is mixed with another substance,so it can never be negative.
CaCl2(aq) + Pb(NO3)2(aq) ===> Ca(NO3)2(aq) + PbCl2(s) so a precipitate of PbCl2 (lead chloride) will form. The fact that equal volumes of 0.2 M are mixed indicates that all of the Pb^2+ and all of the Cl^- will precipitate out of solution leaving only Ca^2+ and NO3^- left in solution.
You get 1 Mole Of Calcium Carbonate "Chalk", along with 2 Moles of Sodium Chloride "Salt" Na2CO3 + CaCl2 -------------> CaCO3 + 2NaCl
The reaction is: CaCO3 + 2HCl = CaCl2 + H2O + CO2
When a soluble salt is mixed in water, we call it a solution. This differs from a pure liquid because normally we would like to describe a salt solution as having some kind of concentration.
BaCl2- and KCl-solutions have no color, and also none when mixed.
If place in a hypertonic solution it would swell and/or burst because to much water is getting in the cell from the hypertonic solution ( osmosis ). If placed in a hypotonic solution it will end up shrinking from the water leaving the cell to the hypotonic solution ( again osmosis ). Osmosis is when water moves to a lower pressure of water so if there's more water pressure in the cell it will move out into the less dense solution. :)
a completely mixed reactor. the concentration in the reactor is the same that flows our of the reactor