100 mL of solution 1 M mixed with 900 mL distilled water
Molar mass is 44. Linear Formula of PVA is [-CH2CHOH-]n. As C=12 O=16 H=01 Hence (12+2+12+1+16+1=44)
There is 0.5 moles of NaOH per litre To calculate 0.5 molar NaOH first know the molecular weight of NaOH i.e 40 now multiply the number of moles of NaOH you have (0.5) found as above. so to find the number of grams of NaOH we needed to start with (0.5) * (40) = 20g So dissolve 20g of NaOH in one litre of the solution to prepare 0.5 molar solution
1. Find molar mass of FeSO4 = 152g (rounded) 2. Convert mL to L 20 mL / 1000 = .020 L 3. (.500 M/L) (.020) = .01 mol FeSO4 x 152g/mol = 1.52 g FeSO4 Answer = 1.52 g FeS04
Molartiy = moles of solute/Liters of solution200 mL X (1 Liter/10^2)= 0.200 Liters0.200 Liters x (0.05 M)= .01 moles of NaOH.01 moles of NaOH x (40 g NaOH/ 1 mole NaOH)= 0.4 g NaOH are required
right i dont know this 4 sure but because u want a 0.1 mol/dm3 and u only need 100cm3 u will need 0.01mols of copper sulfate to dilute in 100cm3. soo now u have a solution that is 0.01mols per 100cm3 or 0.1 mols per 1000cm3 (dm3)
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Molar mass is 44. Linear Formula of PVA is [-CH2CHOH-]n. As C=12 O=16 H=01 Hence (12+2+12+1+16+1=44)
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There is 0.5 moles of NaOH per litre To calculate 0.5 molar NaOH first know the molecular weight of NaOH i.e 40 now multiply the number of moles of NaOH you have (0.5) found as above. so to find the number of grams of NaOH we needed to start with (0.5) * (40) = 20g So dissolve 20g of NaOH in one litre of the solution to prepare 0.5 molar solution
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