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How many grams of FeSO4 are in 20 ml sample of a 500 M solution?
Wiki User
∙ 12y ago
1. Find molar mass of FeSO4 = 152g (rounded)
2. Convert mL to L 20 mL / 1000 = .020 L
3. (.500 M/L) (.020) = .01 mol FeSO4 x 152g/mol = 1.52 g FeSO4
Answer = 1.52 g FeS04
Wiki User
∙ 12y ago
Wiki User
∙ 7y ago2o mL of iron(II) nitrate 0,5 M solution contain 2,419 g compound.
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