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The hot water will get colder and the ice will melt and the water from the melted ice will get to the same temperature as the final temperature of the hot water.
the average of the temperatures T(final) = (T1 + T2) / 2
When allowed to stand for long enough, the final temperature will reach room temperature.
Temperature of the water
When allowed to stand for long enough, the final temperature will reach room temperature.
No, as both the temperatures are the same, you will get only 2 cups, each 50 degrees. You have to heat the cup to get 100 degree.
15 degree centigrade
The hot water will get colder and the ice will melt and the water from the melted ice will get to the same temperature as the final temperature of the hot water.
the average of the temperatures T(final) = (T1 + T2) / 2
THE ANSWER IS 62.8 DEGREES.....
This depends on the volume.
The temperature would be that of water's boilng point od 100 degrees
42.3 C
2 liters of water at 20 degrees, provided the mixing was not too vigorous and didn't last too long.
That all depends on what you want the final temperature of the mixture to be. Technically, one single drop of 40-degree water will reduce the temperature of the 800 gallons.
Based on this page, which contains a slightly more complex problem the answer would be 40 degrees, as (60*100+20*100)/(100+100) =40. http://www.crystalgrowing.com/recipes/solution_calculator/solution_calculator.htm
40 degree