Telechenasis
360 joules
60 kg m/s
60/4 pounds or 15 pounds
Work= 1500 Joule. Time= 60 100 N is moved 15 meters. Work = applied force (newtons) x distance (meters) X = 100 x 15 Work = 1500 Joules Power (watts) = work (joules)/ time (seconds) 25 = 1500/X Time = 60.
Let's say the direction of the 10 N force is 0 degrees. The 16 N force has a component of 16 N cos(60°) in the direction of the 10 N force and a component of 16 N sin(60°) in the perpendicular 90° direction. Adding the two gives a √( ((16 cos(60°)+10)2 + (16 sin(60°))2 ) ≅ 22.7 N force in the atan( 16 sin(60°) / (16 cos(60°)+10) ) ≅ 37.6° direction. Counteracting this would require a force of 22.7 N in the 37.6°+180° = 217.6° direction.
360 joules
60
50 billion million gazillion 500 60 trillion newtons
60 kg m/s
-- The sum of the two given forces is44cos(60) in the x-direction33 + 44sin(60) in the y-direction.-- The components of the third force must be-44cos(60) in the x-direction-33 - 44sin(60) in the y-direction-- The magnitude2 of the unknown force is[-44cos(60)]2 + [-33 - 44sin(60)]2 = (484) + (5,055.94) = 5539.94Magnitude = 74.43 newtons.-- The angle of the third force istan-1 [-33-44sin(60)/-44cos(60)] = tan-1 (3.232) into the 3rd Quadrant = 72.8+180 = 252.8° .
60/4 pounds or 15 pounds
60
60:13
50% of 120 id 60 40% of 60 is 24.
F = ma so F = 10kg x 6m/s^2 = 60 kgm/s^2 or 60 Newtons
Work= 1500 Joule. Time= 60 100 N is moved 15 meters. Work = applied force (newtons) x distance (meters) X = 100 x 15 Work = 1500 Joules Power (watts) = work (joules)/ time (seconds) 25 = 1500/X Time = 60.
60