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What will the stopping distance be for a 3000kg car if -3000 N of force are applied when the car is traveling 10ms?
The stopping distance can be calculated using the equation: stopping distance = (initial velocity^2) / (2 * deceleration). The deceleration can be calculated using the formula: deceleration = force / mass. Plugging in the values and calculating will give you the stopping distance.
What can you pick up by exerting 1 newton?
The short answer is:A mass with a weight of 1 Newton such as a small apple.A longer answer is:On average a mass of 101.9g on Earth although it will depend a bit exactly where you are, the force of gravity varies a little from place to place even on the surface of the Earth. On the moon it would be a mass of about 616.5g.In high school the acceleration due to gravity on Earth is often simplified to 10ms-2 rather than the average value of 9.81ms-2. If we use 10ms-2 you get an answer of 100g.
What will the stopping distance be for a kg car if -3000 N of force are applied when the car is traveling 10ms?
To calculate stopping distance, we need to first find the deceleration of the car using the formula: force = mass x acceleration. Given that force = -3000 N and mass = kg, we can find the acceleration. Once the acceleration is known, we can use the equation of motion: final velocity^2 = initial velocity^2 + 2 x acceleration x distance to calculate the stopping distance.
How is force calculated?
Force in terms of newtons is expressed in the equation f=ma, that is, force (newtons) = Mass (kilograms) x Acceleration (MS-2, meters per second per second). This refers to the force needed to exert on something to increase its speed disregarding friction as a form of negative force. To work out the force applied by something when it causes impact, Forcei = mass x speed. Say a 100kg object is travelling at 10ms-1 , it is exerting a force of 1000 newtons upon impact, now if it impacts with another person of mass of 50kg, and stops completely, that other person will travel at a speed of 20ms-1 in the same direction that the original person was travelling. hope this helped.
What will the stopping distance be for 3000-kg car if -3000 N of force are applied when the car is traveling 10ms?
To calculate stopping distance, you need to know the deceleration of the car. Here, deceleration can be calculated using Newton's second law: deceleration = force / mass. With the given force of -3000 N and mass of 3000 kg, the deceleration would be -1 m/s^2. Using the equation of motion, final velocity^2 = initial velocity^2 + 2 * acceleration * distance, you can calculate the stopping distance.
An RC circuit has a time constant of 10ms and an applied voltage of 15V What is the voltage on the capacitor after one time constant?
About 5.5 volts.
What will the stopping distance be for a 3000kg car if -3000 N of force are applied when the car is traveling 10ms?
The stopping distance can be calculated using the equation: stopping distance = (initial velocity^2) / (2 * deceleration). The deceleration can be calculated using the formula: deceleration = force / mass. Plugging in the values and calculating will give you the stopping distance.
How can you determine the amount of force exerted?
To find the force on an object, you multiple the mass of the object by its accelerationFor example, let's say a ball is moving at 7 m/s squared and has a mass of12 kg.The formula for force is: F = maF = 12 kg x 7 m/s squaredF = 84 N ( the unit for force is N, which is Newtons)*Be careful, an object does not "have a force". A force is an action that can modify the shape of an object and/or modify its velocity. Therefore, you do not calculate the force of an object, but the force required to give it a certain acceleration.
What can you pick up by exerting 1 newton?
The short answer is:A mass with a weight of 1 Newton such as a small apple.A longer answer is:On average a mass of 101.9g on Earth although it will depend a bit exactly where you are, the force of gravity varies a little from place to place even on the surface of the Earth. On the moon it would be a mass of about 616.5g.In high school the acceleration due to gravity on Earth is often simplified to 10ms-2 rather than the average value of 9.81ms-2. If we use 10ms-2 you get an answer of 100g.
What will the stopping distance be for a kg car if -3000 N of force are applied when the car is traveling 10ms?
To calculate stopping distance, we need to first find the deceleration of the car using the formula: force = mass x acceleration. Given that force = -3000 N and mass = kg, we can find the acceleration. Once the acceleration is known, we can use the equation of motion: final velocity^2 = initial velocity^2 + 2 x acceleration x distance to calculate the stopping distance.
Which is bigger 0.05 millisecond or 0.05 centisecond?
centisecond = cs millisecond = ms 1cs = 10ms 0.05ms x 1cs/10ms = 0.005cs The 0.05cs is larger than the 0.05ms.
What is the Rockwell hardness range for CD4MCu castings?
10ms to 560ms
How is force calculated?
Force in terms of newtons is expressed in the equation f=ma, that is, force (newtons) = Mass (kilograms) x Acceleration (MS-2, meters per second per second). This refers to the force needed to exert on something to increase its speed disregarding friction as a form of negative force. To work out the force applied by something when it causes impact, Forcei = mass x speed. Say a 100kg object is travelling at 10ms-1 , it is exerting a force of 1000 newtons upon impact, now if it impacts with another person of mass of 50kg, and stops completely, that other person will travel at a speed of 20ms-1 in the same direction that the original person was travelling. hope this helped.
What will the stopping distance be for 3000-kg car if -3000 N of force are applied when the car is traveling 10ms?
To calculate stopping distance, you need to know the deceleration of the car. Here, deceleration can be calculated using Newton's second law: deceleration = force / mass. With the given force of -3000 N and mass of 3000 kg, the deceleration would be -1 m/s^2. Using the equation of motion, final velocity^2 = initial velocity^2 + 2 * acceleration * distance, you can calculate the stopping distance.
What determines the magnitude of the normal force?
The normal force if the force of one object holding up anothe. Ex. a block of wood on the ground. The normal force is the force applied to the wood to prevent it from sinking. In other words, it is the objects weight. W=mg, where W=weight, m=mass, g=force of gravity.
A wavelength of 0.5hz and a speed 10ms has a wavelength of?
Wavelength = Velocity(or speed)/frequencysoWavelength= 10/0.5=20m
What is the acceleration of a hockey player who is skating at 10ms and comes to a stop in 2 seconds?
-2.5 m/s/s
