Telechenasis
60 newtons is a unit of force in the International System of Units (SI) equivalent to approximately 13.48 pounds-force. It is commonly used to measure the force applied to an object.
The acceleration of an object depends on the force acting on it. If a force is applied, the acceleration can be calculated using Newton's second law: acceleration = force / mass. More information about the force acting on the object is needed to determine its acceleration.
The force needed to accelerate the 60 kg object at 10 m/s^2 is 600 N. This is calculated using Newton's second law: force = mass x acceleration.
In that case, just use the (basic) definition of work: multiply force x distance. The answer is in joules. This assumes that (a) the force acts in the same direction as the movement (otherwise, the dot product must be used), and (b) the force is constant (otherwise, an integral must be used).
The work done by a force is given by the formula W = Fdcos(theta), where F is the force, d is the displacement, and theta is the angle between the force and displacement. Given F = 40 N, d = 1 m, and theta = 60 degrees, plug in these values to get W = 401cos(60). Calculate the value of cos(60) (which is 0.5) and compute the work done. Therefore, W = 40 * 1 * 0.5 = 20 Joules.
60 newtons is a unit of force in the International System of Units (SI) equivalent to approximately 13.48 pounds-force. It is commonly used to measure the force applied to an object.
The acceleration of an object depends on the force acting on it. If a force is applied, the acceleration can be calculated using Newton's second law: acceleration = force / mass. More information about the force acting on the object is needed to determine its acceleration.
The force needed to accelerate the 60 kg object at 10 m/s^2 is 600 N. This is calculated using Newton's second law: force = mass x acceleration.
50 billion million gazillion 500 60 trillion newtons
60
In that case, just use the (basic) definition of work: multiply force x distance. The answer is in joules. This assumes that (a) the force acts in the same direction as the movement (otherwise, the dot product must be used), and (b) the force is constant (otherwise, an integral must be used).
-- The sum of the two given forces is44cos(60) in the x-direction33 + 44sin(60) in the y-direction.-- The components of the third force must be-44cos(60) in the x-direction-33 - 44sin(60) in the y-direction-- The magnitude2 of the unknown force is[-44cos(60)]2 + [-33 - 44sin(60)]2 = (484) + (5,055.94) = 5539.94Magnitude = 74.43 newtons.-- The angle of the third force istan-1 [-33-44sin(60)/-44cos(60)] = tan-1 (3.232) into the 3rd Quadrant = 72.8+180 = 252.8° .
60
The work done by a force is given by the formula W = Fdcos(theta), where F is the force, d is the displacement, and theta is the angle between the force and displacement. Given F = 40 N, d = 1 m, and theta = 60 degrees, plug in these values to get W = 401cos(60). Calculate the value of cos(60) (which is 0.5) and compute the work done. Therefore, W = 40 * 1 * 0.5 = 20 Joules.
To lift a 60 pound rock with a mechanical advantage of 4, you would need to apply 15 pounds of force. This is because the force needed is the weight of the rock divided by the mechanical advantage (60 pounds / 4 = 15 pounds).
The work done by a force can be calculated using the formula: Work = Force x Distance x cos(theta), where theta is the angle between the force and the direction of motion. Assuming the force is in the direction of motion (theta = 0), the work done would be 360 Joules (60 N * 6 m).
50% of 120 id 60 40% of 60 is 24.