If it would have existed it formula would have been NH4CrO4
The formula for cobalt(III) chromate is Co2(CrO4)3.
The compound with formula CoCrO4 is named cobalt (II) chromate or cobaltous chromate.
Ammonium ions have a charge of +1 and Chromate ions have a charge of -2. When these ions react, they form Ammonium Chromate; 2NH4CrO4
NiCrO4
PbCrO4
Ammonium chromate = (NH4)2CrO4
Ammonium Chromate = (NH4)2CrO4
Lead(II) Chromate = PbCrO4
The formula for cobalt(III) chromate is Co2(CrO4)3.
(NH4)2 CrO4 But I do not know why de ammonium has 2 molecules.......and that´s my question....
MnCrO4 is manganese(II) chromate
The compound with formula CoCrO4 is named cobalt (II) chromate or cobaltous chromate.
The chemical formula for Iron(II) Chromate would be FeCrO4.
(NH4)2CrO4
(NH4)2CrO4
Ammonium ions have a charge of +1 and Chromate ions have a charge of -2. When these ions react, they form Ammonium Chromate; 2NH4CrO4
NiCrO4