Chromium has four oxidation states: 2, 3, 4, and 6. Chlorine has one, and it's -1. There will be a chloride for each oxidation state of chromium. Here they are: CrCl2 Chromium (II) chloride CrCl3 Chromium (III) chloride CrCl4 Chromium (IV) chloride CrCl6 Chromium (VI) chloride
Chromium has six oxidation states. Cr(I); Cr(II); Cr(III); Cr(IV); Cr(V) and Cr(VI).
The next question is which of these oxidation states will bond with fluorine?
A further question is will they form pure fluorides or is some other element necessary for bonding?
Chemistry is complicated especially when dealing with transition metals like chromium.
CrF5 exists, that is Cr(V), a volatile compound. And there is a fluoride of Cr(IV), CrF62+. CrCl4 is an unstable compound so perhaps there is a similar CrF4.
CrF3 is a Cr(III) fluoride. Chromium (III) is the most stable oxidation state. Cr(I) and Cr(II) may have fluorides CrF and CrF2 but Cr(VI) is unlikely to have fluorides as its compounds are strong oxidizing agents, it tends to take rather than donate electrons. Example of Cr(VI) is dichromate ion, Cr2O72-.
I think the correct formula is Cr(ClO3)3 but I also think it is only stable in aqueous solution, violently decomposing to chromium chloride CrCl3 and O2 (g) if the water is driven off by heat, or allowed to evaporate. I get this by analogy to potassium chlorate and its decomposition to salt and oxygen; and from the fact that if you make a small amount of paste from chromium oxide and dilute HCl on a tin can lid and heat that over a flame, you get a very satisfactory explosion, consistent with the above. Dane Brooke
CrO since the subscripts cancel out but the question really should not be asking what is the formula for chromium oxide, it should be asking what is the formula for Chromium(II)Oxide
The formula for chromium III bromide hexahydrate is CrBr3·6H2O
Formula: Cr(ClO3)3
CrCl2
CrCl3
Chromium(III) Bromide
chromium (III) bromide calcium chloride OR iron (III) oxide aluminum chloride
AlBr3 is the formula for aluminum (III) bromide.
Gold (III) bromide has the chemical formula AuBr3. It usually exists as a dimer with the formula Au2Br6. Gold (III) bromide may be used as a catalyst for Diels-Alder reactions.
Chromium(III) nitrate is Cr(NO3)3
Cr2O3 is the chemical formula for chromium (III) oxide
Chromium(III) Bromide
Chromium(III) Bromide
Chromium (III) Bromide
chromium (III) bromide calcium chloride OR iron (III) oxide aluminum chloride
BaBr2Barium bromide
AlBr3 is the formula for aluminum (III) bromide.
Fe3+(CH3COO-)3.6H2O
Tin (III) bromide, if it exists, has the formula SnBr3.
Formula: AuBr3
Formula: FeBr3
ferric bromide or iron(III) bromide. CAS No. 10031-26-2 ((FeBr3))Molecular Formula: Br3FeMolecular Weight: 295.557