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Chromium has four oxidation states: 2, 3, 4, and 6. Chlorine has one, and it's -1. There will be a chloride for each oxidation state of chromium. Here they are: CrCl2 Chromium (II) chloride CrCl3 Chromium (III) chloride CrCl4 Chromium (IV) chloride CrCl6 Chromium (VI) chloride

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16y ago
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12y ago

Chromium has six oxidation states. Cr(I); Cr(II); Cr(III); Cr(IV); Cr(V) and Cr(VI).

The next question is which of these oxidation states will bond with fluorine?

A further question is will they form pure fluorides or is some other element necessary for bonding?

Chemistry is complicated especially when dealing with transition metals like chromium.

CrF5 exists, that is Cr(V), a volatile compound. And there is a fluoride of Cr(IV), CrF62+. CrCl4 is an unstable compound so perhaps there is a similar CrF4.

CrF3 is a Cr(III) fluoride. Chromium (III) is the most stable oxidation state. Cr(I) and Cr(II) may have fluorides CrF and CrF2 but Cr(VI) is unlikely to have fluorides as its compounds are strong oxidizing agents, it tends to take rather than donate electrons. Example of Cr(VI) is dichromate ion, Cr2O72-.

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15y ago

I think the correct formula is Cr(ClO3)3 but I also think it is only stable in aqueous solution, violently decomposing to chromium chloride CrCl3 and O2 (g) if the water is driven off by heat, or allowed to evaporate. I get this by analogy to potassium chlorate and its decomposition to salt and oxygen; and from the fact that if you make a small amount of paste from chromium oxide and dilute HCl on a tin can lid and heat that over a flame, you get a very satisfactory explosion, consistent with the above. Dane Brooke

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11y ago

CrO since the subscripts cancel out but the question really should not be asking what is the formula for chromium oxide, it should be asking what is the formula for Chromium(II)Oxide

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8y ago

The formula for chromium III bromide hexahydrate is CrBr3·6H2O

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13y ago

Formula: Cr(ClO3)3

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12y ago

CrCl2

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15y ago

CrCl3

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Q: What is the formula for chromium III bromide hexahydrate?
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