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Assuming that the abbreviation "NT" means "net tons" or some other unit of mass or weight and that the percentages are by weight or mass, this is essentially an algebra problem. Call the unknown amount of copper x in NT. Since the original mix contains 0.20 % of copper, its copper content is 0.0020 X 165 = 0.330 NT. Then 0.33 + x = 0.0021 X (165 + x), or 0.33 + x = 0.346 + 0.0021x, or 0.9979x = 0.346 - 0.330, or x = 0.016 NT of copper. Using U. S. tons of 2000 pounds each, this equals 32 pounds.

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Q: What is the formula for determining how many pounds of copper raises the Cu percent in a 165 NT ladle of steel from .20 to .21 percent?
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