This question has not been answered properly. The previous answer has been removed on the grounds that it was not informative and insulting.
Based on a alacritous search I have yet to find solid evidence that such a compound is possible.
The chemical formula for tin(II) carbonate is SnCO3.
Sn(OH)2
SnCl2
The chemical name for SnCO3 is tin(II) carbonate.
The chemical formula for Mercury II Carbonate is HgCO3.
The formula for germanium(II) carbonate is GeCO3.
The formula for tin(II) bromide is SnBr2. It consists of one tin atom and two bromine atoms.
The correct formula for Lead(II) Carbonate is PbCO3.
The formula for the compounds: Chromium (VI) Phosphate; Vanadium (IV) Carbonate; Tin (II) Nitrite?
The chemical name for SnCO3 is tin(II) carbonate.
The chemical formula for Mercury II Carbonate is HgCO3.
The formula for germanium(II) carbonate is GeCO3.
The formula of iron II hydroxide is Fe (OH) 2
Tin has two oxidation states (II and IV), and exhibits approximately equal stability in both its II and IV oxidation state. The chemical formula Tin (II) Iodide is SnI2. The chemical formula for Tin (IV) Iodide is SnI4.
It is ZrCO3.
Iron(II) carbonate
The chemical formula for tin(II) sulfate is SnSO4.
The ionic formula for tin (II) bromide is SnBr2. This compound consists of one tin(II) ion (Sn2+) and two bromide ions (Br-).
The answer, barium II carbonate is wrong for the formula BaCO3 because barium has only one possible charge.
Sn(CLO3)2 Tin (II) has a positive 2 charge and Chlorate has a (-1) charge so you need to cholrates to one Tin.