This question has not been answered properly. The previous answer has been removed on the grounds that it was not informative and insulting.
Based on a alacritous search I have yet to find solid evidence that such a compound is possible.
Sn(OH)2
SnCl2
HgCo3
Sn(CLO3)2 Tin (II) has a positive 2 charge and Chlorate has a (-1) charge so you need to cholrates to one Tin.
Tin (II) cyanide has the formula Sn(CN)2.
The chemical Formula for Cobalt II hydrogen carbonate can be given.It is as follows :Co2HCO3.
The chemical formula for Tin(II) Bromide is SnBr2.
The formula for the compounds: Chromium (VI) Phosphate; Vanadium (IV) Carbonate; Tin (II) Nitrite?
The formula of iron II hydroxide is Fe (OH) 2
It is ZrCO3.
Iron(II) carbonate
HgCo3
Tin has two oxidation states (II and IV), and exhibits approximately equal stability in both its II and IV oxidation state. The chemical formula Tin (II) Iodide is SnI2. The chemical formula for Tin (IV) Iodide is SnI4.
The answer, barium II carbonate is wrong for the formula BaCO3 because barium has only one possible charge.
Sn (Tin) and C (Carbon) don't normally occur together. The closest reference I could find was to "Tin-Doped Carbon Clusters" in a chemistry journal.
nickel (ii) carbonate
SnF2
Sn(CLO3)2 Tin (II) has a positive 2 charge and Chlorate has a (-1) charge so you need to cholrates to one Tin.
The chemical formula for tin sulphide is SnS