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The equation for half-life is ...

AT = A0 2(-T/H)

... where A0 is the starting activity, AT is the ending activity at some time T, and H is the half-life in units of T.

Given that A0 is 1, H is 27 seconds, and T is 86400 seconds (one day, or 24 hours), AT is simply 5.06x10-964.

This sounds a bit extreme, and perhaps the question was mis-stated, but that's what the equation produces.

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Q: What is the formula to calculate the remaining mass of an isotope with a half life of 27 seconds after 24 hours?
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