The equation for half-life is ...
AT = A0 2(-T/H)
... where A0 is the starting activity, AT is the ending activity at some time T, and H is the half-life in units of T.
Given that A0 is 1, H is 27 seconds, and T is 86400 seconds (one day, or 24 hours), AT is simply 5.06x10-964.
This sounds a bit extreme, and perhaps the question was mis-stated, but that's what the equation produces.
Yes, but it has a halflife of only 0.86 seconds.
In order to have an equation, we need to know what isotope of neon we are dealing with. Neon 2 is not an isotope.
THE QUESTION IS INVALID. THE HALF-LIFE OF FLUORINE-20 is 11.07 SECONDS. There will be about 0.92 of of an isotope with a half-life of 114 seconds remaining after 14 seconds. The equation for half-life decay is AT = A0 2(-T/H) where T is time and H is half-life. 2(-14/114) is equal to about 0.92. In the case of fluorine-20, 2(-14/11.07) is about 0.42.
The most stable isotope is 285Cn, which has a half life of 30 seconds. The least stable isotope is 277Cn, which has a half life of 0.7 milliseconds.
If you count the number of times it spins in 60 seconds, you find out each rotation is .1mph. So for example it spins 65 times in 60 seconds you can calculate the wind speed in 6.5mph.
Isotope A
You can't convert between seconds, and meters/second. If you have a problem that involves speeds, use the formula: distance = speed x time.
Yes, but it has a halflife of only 0.86 seconds.
MPH = miles per hour. In order to calculate hours from seconds, you just need to know that there are 3,600 seconds in an hour.
In order to have an equation, we need to know what isotope of neon we are dealing with. Neon 2 is not an isotope.
(4 coulombs / 2 seconds) = 2 coulombs per second = 2 Amperes.
Seconds/3600 = Hours
THE QUESTION IS INVALID. THE HALF-LIFE OF FLUORINE-20 is 11.07 SECONDS. There will be about 0.92 of of an isotope with a half-life of 114 seconds remaining after 14 seconds. The equation for half-life decay is AT = A0 2(-T/H) where T is time and H is half-life. 2(-14/114) is equal to about 0.92. In the case of fluorine-20, 2(-14/11.07) is about 0.42.
hours x 3,600 = seconds
Multiply by 24x60x60. This is 86400 seconds in a day.
California
The most stable isotope is 285Cn, which has a half life of 30 seconds. The least stable isotope is 277Cn, which has a half life of 0.7 milliseconds.