I=v/r
There are several formulas to find out leakage current, but one is the general electric current equation. This electric current equation is I=Qt.
To find the energy dissipated in a resistor, you can use the formula: Energy (current)2 x resistance x time. This formula calculates the energy dissipated in the resistor based on the current flowing through it, the resistance of the resistor, and the time the current flows.
To find the current in the circuit, you can use the formula: Power = Current^2 * Resistance. Given the values, you can rearrange the formula to solve for current: Current = sqrt(Power / Resistance). Plugging in the values, you get Current = sqrt(2 / 30) which simplifies to approximately 0.27 amperes.
The dimensional formula of electric current is [I] = [A], where I represents current and A represents ampere.
To find watts in physics, you can use the formula: Watts Volts x Amps. This formula calculates power, which is measured in watts, by multiplying the voltage (in volts) by the current (in amps) flowing through a circuit.
To find the amperage, use the formula: Power (W) = Voltage (V) x Current (A). Rearranging the formula to solve for current gives: Current (A) = Power (W) / Voltage (V). So, with 10kW at 220V, the current drawn would be 45.45A.
I don't think you can do that, with the information provided.
You can find baby formula coupons almost every week in the newspaper. You can also get them from writing to the company, or inside the package of current products.
Water heaters come in many sizes. Look for the wattage of the heater and use the following formula to find the current. I = W/E = Watts/Volts. As you can see a voltage and wattage of the tank is needed to find the current.
current ratio = current asset divided by current liability
Formula for current ratio is as follows: Current ratio = Current assets / current liabilities
Since power is the product of voltage and current, you will need to find out the power rating of the headlamp when on low beam. To find the current, divide the power of the lamp by the voltage (12 V).