The formula you are looking for is I = W/E. Amps = Watts/Volts.
45-50 amps. But your overcurrent protection and wire must be designed for 125% of load so the max overcurrent protection is 55 amps or 60
To calculate the amperage for a 10kW heater on a 3-phase 220V system, use the formula: Amps = (kW x 1000) / (√3 x Volts). So, Amps = (10 x 1000) / (√3 x 220) = 26.18 amps per phase. Therefore, the total current drawn by the heater is 26.18 amps per phase multiplied by 3, which equals approximately 78.54 amps.
Watts is found by multiplying the volts by the amps. Normally a supply is provided at a fixed voltage, and the amount of current that is drawn depends on how many watts the equpiment requires.
The amps drawn by a 65 watt light bulb should be 65/120 or 0.54167. This fraction of an ampere may be restated as 541.67 milli-amps.
Depends on the supply voltage. For UK 230 Volts, 1800 Watts would mean the current drawn was 7.83 Amps.Watts=Volts x Amps, so Watts divided by Volts gives the current in amps.
The formula you are looking for is I = W/E. Amps = Watts/Volts. As you can see a voltage must be stated to answer this question. 10kW = 10000 watts.
45-50 amps. But your overcurrent protection and wire must be designed for 125% of load so the max overcurrent protection is 55 amps or 60
To calculate the amperage for a 10kW heater on a 3-phase 220V system, use the formula: Amps = (kW x 1000) / (√3 x Volts). So, Amps = (10 x 1000) / (√3 x 220) = 26.18 amps per phase. Therefore, the total current drawn by the heater is 26.18 amps per phase multiplied by 3, which equals approximately 78.54 amps.
Watts = Volts times Amps. Therefore, if the voltage was 220 volts, the motor would draw 500 amps. If the voltage was 4,000 volts, the motor would draw 27.5 amps. The voltages for large powerful motors tend to be relatively high, for example in the 380 Volts to 11,500 Volts range.
Watts is found by multiplying the volts by the amps. Normally a supply is provided at a fixed voltage, and the amount of current that is drawn depends on how many watts the equpiment requires.
The amps drawn by a 65 watt light bulb should be 65/120 or 0.54167. This fraction of an ampere may be restated as 541.67 milli-amps.
160 amps at 12v.
160 amps at 12v.
Depends on the supply voltage. For UK 230 Volts, 1800 Watts would mean the current drawn was 7.83 Amps.Watts=Volts x Amps, so Watts divided by Volts gives the current in amps.
Ohm's law: Volts = Amps * Ohms, or Amps = Volts / Ohms 12 volts / 0.5 ohms = 24 amps
4 volts and how many amps? Watts = amps x volts. It depends on the amount of current (in Amps) flowing at 4 Volts... See Ohms Law: Watts = Volts x Amps If you have 2 Amps flowing at 4 Volts you are dissipating/consuming 8 Watts. If you have 10 Amps flowing at 4 Volts you are dissipating/consuming 40 Watts.
To determine how many amps are in 115 volts, you need to know the power (in watts) being used. The relationship between volts, amps, and watts is given by the formula: Watts = Volts × Amps. Therefore, to find the amps, you can rearrange the formula: Amps = Watts / Volts. For example, if you have a device that uses 1150 watts, you would have 10 amps at 115 volts (1150 watts ÷ 115 volts = 10 amps).