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The energy of a photon is inversely propotional to its wavelength. The wavelength of a blue photon is less than that of a red photon. That makes the blue photon more energetic. Or how about this? The energy of a photon is directly proportional to its frequency. The frequency of a blue photon is greater than that of a red photon. That makes the blue photon more energetic. The wavelength of a photon is inversely proportional to its frequency. The the longer the wavelength, the lower the frequency. The shorter the wavelength, the higher the frequency.
No, it could not. A blue photon carries more energy than a red photon, since the blue photon's frequency is higher. That means one red photon wouldn't deliver enough energy to the atom to give it the energy to emit a blue photon.
Wavelength is speed, of light, in this case, divided by frequency. 3 x 108 meters per second divided by 6.82 x 1014 Hertz is 0.4 micrometers.
All particles which represents a quantum of light and other electromagnetic radiation is called photon. The photons with the highest energies are gamma or X-rays, UV light, Blue light, and radio waves.
A rough definition of intensity (how intense) a light is might be how bright (the brightness) the light is. Intensity speaks to the luminance or luminosity of the light source. Under that definition, either red or blue light could be more intense. But if the information regarding the energy of light according to its color (or its wavelength or frequency), we would find that a photon of blue light has more energy than a photon of red light. Blue light has a shorter wavelength or higher frequency, and electromagnetic energy with higher frequency or shorter wavelength has more energy than light of the same intensity but of lower frequency or longer wavelength.
The energy of a photon is inversely propotional to its wavelength. The wavelength of a blue photon is less than that of a red photon. That makes the blue photon more energetic. Or how about this? The energy of a photon is directly proportional to its frequency. The frequency of a blue photon is greater than that of a red photon. That makes the blue photon more energetic. The wavelength of a photon is inversely proportional to its frequency. The the longer the wavelength, the lower the frequency. The shorter the wavelength, the higher the frequency.
No, it could not. A blue photon carries more energy than a red photon, since the blue photon's frequency is higher. That means one red photon wouldn't deliver enough energy to the atom to give it the energy to emit a blue photon.
Wavelength Frequency and Photon Energy
Wavelength is speed, of light, in this case, divided by frequency. 3 x 108 meters per second divided by 6.82 x 1014 Hertz is 0.4 micrometers.
Just divide the speed of light (in meters/second) by the frequency (in hertz) - that will give you the wavelength (in meters). You can then convert that to nm.
Each photon of blue light has more energy than a photon of any other color, because the blue ones have the highest frequency.
The blue light has longer wavelength, lower frequency, andless energy per photon than the ultraviolet light has.The blue light is also visible to the human eyes, whereas theultraviolet light is not.
If the color (frequency, wavelength) of each is the same, then each photon carries the same amount of energy. Three of them carry three times the energy that one of them carries.
In the spectrum of electromagnetic radiation the wave property that changes is the frequency. So for example xrays have higher frequency then blue light which has higher frequency then red light which has higher frequency then radio waves etc.
All particles which represents a quantum of light and other electromagnetic radiation is called photon. The photons with the highest energies are gamma or X-rays, UV light, Blue light, and radio waves.
A rough definition of intensity (how intense) a light is might be how bright (the brightness) the light is. Intensity speaks to the luminance or luminosity of the light source. Under that definition, either red or blue light could be more intense. But if the information regarding the energy of light according to its color (or its wavelength or frequency), we would find that a photon of blue light has more energy than a photon of red light. Blue light has a shorter wavelength or higher frequency, and electromagnetic energy with higher frequency or shorter wavelength has more energy than light of the same intensity but of lower frequency or longer wavelength.
It is not meaningful to talk about "amplitude of the visible light spectrum". One might think that more intense light would mean greater amplitude of the light wave, but it just means more photons. "Visible light" is made up of photons. A single photon has a certain quantifiable energy, and that energy is discussed in terms of frequency or wavelength. A photon with low frequency (towards the red end of the visible light spectrum, for instance) is less energetic than a photon with high frequency (towards the blue end and beyond). For all intents and purposes, the amplitude of a photon wave-packet could be said to be of "unit amplitude", the amplitude of light.