It is either infrared (below 400THz) or ultraviolet (above 789THz).
Red and blue are at opposite ends of the visible light spectrum, red being of low frequency, and blue being of high frequency. Sunlight contains frequencies across the whole frequency range, which appears white. An object that appears white reflects all frequencies. A red object appears red because it reflects red (low frequency) light, and absorbs all other colours. Blue light contains only high frequencies. If you are in a darkened room, lit only by blue light, white objects will appear blue because they are reflecting the blue light, and no other frequency is available. But a red object absorbs high-frequency (blue) light, and since this is the only light in the room, it does not reflect any light. Objects that do not reflect any light appear black. Some objects appear black even in sunlight, because they absorb all frequencies and do not reflect any. So to answer the question, when you have a red object that is lit only by blue light, it will appear black.
The frequency range for visible light is 400-790 THz
The range is 526-606 THz.
Light is not a mechanical wave. So no need to have a material medium to pass through. Even through vacuum light can travel. Because it is an electromagnetic wave. As electrical and magnetic disturbance pass on in the form of transverse wave the distance between successive crests is defined as the wavlength of the wave. Here crest means the field intensity becoming maximum.
Most of sunlight is in the visible range of the spectrum. A black object by definition absorbs all visible light, while a white object reflects all visible light. The black object absorbs most of the energy from sunlight, turning it into heat.
Red and blue are at opposite ends of the visible light spectrum, red being of low frequency, and blue being of high frequency. Sunlight contains frequencies across the whole frequency range, which appears white. An object that appears white reflects all frequencies. A red object appears red because it reflects red (low frequency) light, and absorbs all other colours. Blue light contains only high frequencies. If you are in a darkened room, lit only by blue light, white objects will appear blue because they are reflecting the blue light, and no other frequency is available. But a red object absorbs high-frequency (blue) light, and since this is the only light in the room, it does not reflect any light. Objects that do not reflect any light appear black. Some objects appear black even in sunlight, because they absorb all frequencies and do not reflect any. So to answer the question, when you have a red object that is lit only by blue light, it will appear black.
The frequency range for visible light is 400-790 THz
The frequency range of visible light.
The range is 526-606 THz.
Yes. The color white in light represents all visible frequencies.The reason that a "white" object appears "colorless" is that it is reflecting the entire range of colors. A "black" object is reflecting much less light, absorbing light energy across the entire range of colors.
Visible light - electromagnetic waves in the frequency range 430 to 770 teraHz.
Wavelengths in the range of 0.4 - 0.7 microns are visible.
the speed of light
Color is the frequency of visible light. The visible light wave range in frequency from 430 trillion hertz, which is red light, to 750 trillion hertz, or violet light.?æ
The frequency of electromagnetic radiation determines whether it is gamma rays, x-rays, radio waves, ultraviolet light, or visible light. Each color of light has its own range of frequencies.
Light is not a mechanical wave. So no need to have a material medium to pass through. Even through vacuum light can travel. Because it is an electromagnetic wave. As electrical and magnetic disturbance pass on in the form of transverse wave the distance between successive crests is defined as the wavlength of the wave. Here crest means the field intensity becoming maximum.
This one is fluorescence. The example of high-lighters is that they absorb UV light (so-called "black light") and re-emit at the visual range, yellow, pink, orange. UV is a higher frequency than visible light. Just so you know, there is no process where something absorbs low-frequency and re-emits at a high frequency. The same idea, light being absorbed and re-emitted at a different frequency - has two main types. If it happens immediately, it is "fluorescent" (think highlighters in a black light) If there is a delay, it is "phosphorescence." Both effects and the delay in the second, are the result of quantum mechanics.