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1HP =746 watts power(watts)= current times voltage ... 746x500=373000. 373000/380= 981.58 so 981.58 amps

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You have not supplies sufficient information to answer the question.

The load current depends upon the type of motor(d.c./a.c./ single-phase/ three-phase), and the efficiencyof the motor. Before you can calculate the current, you need to determine the input power to the machine, which is always greater than its output power, which you have described as being 500 hp. Once you have determined the input power, and the type of motor, only then can you can calculate the load current

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11y ago
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12y ago

You did not specify everything needed to perform that calculation, so some things have been assumed, such as power factor (PF) = 0.92, efficiency (EFF) = 0.95, and voltage (three phase delta) = 4160.

  • 125 HP times 746 watts per HP = 93 KW
  • 93 KW divided by PF (0.92) divided by EFF (0.95) = 107 KVA
  • 107 KVA divided by 3 = 36 KVA per winding
  • 36 KVA divided by 4160 V = 8.5 amperes per winding
  • 8.5 amperes times 1.732 (square root of 3) = 14.8 amperes per phase

This is a big motor, requiring special engineering, and most probably a star-delta MCC. You could theoretically run the motor on 480, but then the current would be 128 amperes per phase, drastically increasing the size of the conductors as well as the size of the motor.

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11y ago

746w=1hp so .5hp=373w and I=p/v so 373/380= 981.6mA

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Q: What is the full load amperage of a 500 HP motor at 380 volts?
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