H is a dominant trait for the hair color red. The trait for white hair is recessiv.The parents genotypes are HH x hh.What will the genotype of the offspring be?
Yes - Hh is heterozygous. HH is homozygous, and hh is homozygous.
Hh
The term "hybrid" in biology means one who carries different alleles for the same trait. For example, a hybrid plant's genotype for height is Hh. When crossing two hybrids, we are performing this operation: Hh x Hh. The offsprings' genotypes can vary from: HH Hh hh
a heterozygous gene is a gene with a genotype with two different letters. For example, Hh rather then hh, HH (which are homozygous). Hope this helps. =)
Genotype for straight hair is recessive and for curly hair is dominant. So lets suppose this: h = straight hair H = curly hair Then to get straight hair, for it being a recessive for that characteristic, your children must be hh. If they are Hh, hH, or HH, they will have curly hair You, for having straight hair are hh, your husband can be Hh or HH. If you quickly use Punnett square (http://en.wikipedia.org/wiki/Punnett_square) to see the odds of each possible genotype your children might have, you will have the following: If hh + Hh: 1) hH > curly 2) hh > straight Result: 50% chances of getting straight hair If hh + HH: 1) hH > curly 2) hH > curly Result: 0% chances of getting straight hair So, yes, it is possible.
hh
HH and Hh; Hh & Hh;Hh &hh; HH & hh
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Homozygous dominant.
Yes to the first one, no to the second one. Firstly, widow's peak is caused by a dominant gene while a straight hairline is caused by a recessive gene. Let 'H' be dominant and 'h' be recessive. So for a dominant gene, the trait still will be expressed whether the genotype of the person is homozygous dominant(HH) or heterozygous(Hh). For a recessive gene however, the trait will only be expressed when the genotype of the person is homozygous recessive (hh). So two people with a widow's peak CAN have a child with a stright hairline, provided both of their genotypes are Hh. This is because by crossing their genotypes, they can have a possibility of having child with the genotype HH(widow's peak), Hh(widow's peak), and also hh(straight hairline). The ratio of these three possibilities however, are 1:2:1. So the odds of having a child with a straight hairline in this case is 1:3. If the two people who have widow's peak have the genotype HH or one of them HH and the other Hh, then the possibility of having a child with a straight hairline is 0. This is because by crossing their genotypes together, the genotype of the child will either be HH for the first case, and HH or Hh for the second case. For two people who have a straight hairline, the genotype of both will definitely be homozygous recessive (hh), thus child will definitely have the recessive gene. Therefore, it is not possible for two people with straight hairline to have a child with widow's peak.
Heterozygote X HeterozygoteEg.Hh X Hh- produces HH, 2 Hh, hh = 3 different genotypesWhereas:HH X hh- produces all HhAnd HH X HH- produces all HH